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问题描述

我有多个表。

游览表

  id |标题| slu ..... ..... 

图片表

  id | tour_id |图像..... 

包含表

  id | tour_id |包含.... 

排除表

  id | tour_id |排除... 

Itenary Table

  id | tour_id | day_summary ..... 

Tour_User表(这是一个数据透视表旅游表和用户表)

  tour_id | user_id 

我需要

我想用图片,包含,排除,itenary,tour用户其中 image.tour_id 等于 tour.id 和 inclusion.tour_id 等于 tour.id 和 exclusion.tour_id 等于 tour.id 等。



我将 Tour Model 中的关系定义为

  public function user(){
return $ this-> hasOne(TourUser :: class);


public function image(){
return $ this-> hasMany(TourImage :: class);


public function inclusion(){
return $ this-> hasMany(TourInclusion :: class);


public function exclusion(){
return $ this-> hasMany(TourExclusion :: class);


public function highlight(){
return $ this-> hasMany(TourHighlight :: class);

$ b $ public function itenary(){
return $ this-> hasMany(TourItenary :: class);





$ b

我知道这可以用循环和条件语句来完成,我们需要查询数据库多次,但是我想用Laravel 5.4中的雄辩加载来实现它。我该如何实现它。 这似乎有点类似的问题,但不能解决方案。



我试过类似的东西:

  $ tour = Tour ('slug',$ slug)
- > with('user','image','itenary','inclusion','exclusion')
- > whereHas(' ('user_id',user() - > id);})< - user()在登录用户的帮助函数中定义详细信息
- > whereHas('itenary',function($ query){
$ query-> where('tour_id','21');})< - pass tour id
- > whereHas('inclusion',function($ query){
$ query-> where('tour_id','21');})< - pass tour id
- > first();


解决方案

在Laravel上你不能这样做,因为关系是有很多



您应该这样做:

($'$'),$($'$' $(user_id),user() - > id);
})< - user()在助手函数中定义用于登录的用户详细信息
- > whereHas ('itenary',函数($ query){
$ query->其中('tour_id','21');
})< - 通过游览ID
- > ; whereHas('inclusion',function($ query){
$ query-> where('tour_id','21');
})< - 传入游览ID
- >首先();

$ images = $ tour->图片;
$ inclusions = $ tour->包含;
$ exclusions = $ tour->排除;
$ highlights = $ tour-> highlight;
$ itenaries = $ tour-> itenary;


I have multiple tables.

Tour Table

id | title | slug .....

Image Table

id | tour_id | image.....

Inclusion Table

id | tour_id | inclusion....

Exclusion Table

id | tour_id | exclusion...

Itenary Table

id | tour_id | day_summary.....

Tour_User Table (This is a pivot table between tour table and user table)

tour_id | user_id

I Need

I want to get tour details with image, inclusion, exclusion, itenary, tour user where image.tour_id equals tour.id and inclusion.tour_id equals tour.id and exclusion.tour_id equals tour.id and so on.

I have defined relationship in Tour Model as

public function user() {
        return $this->hasOne(TourUser::class);
    }

    public function image() {
        return $this->hasMany(TourImage::class);
    }

    public function inclusion() {
        return $this->hasMany(TourInclusion::class);
    }

    public function exclusion() {
        return $this->hasMany(TourExclusion::class);
    }

    public function highlight() {
        return $this->hasMany(TourHighlight::class);
    }

    public function itenary() {
        return $this->hasMany(TourItenary::class);
    }

I know this can be done with looping and conditional statements where we need to query the database multiple times, but I want to achieve it with `eager loading with eloquent in Laravel 5.4 How can I achieve it. https://stackoverflow.com/a/21380265/4807414 this seem to have have a bit similar problem but couldn't solve.

I tried something like:

$tour = Tour::where('slug', $slug)
                    ->with('user', 'image', 'itenary', 'inclusion', 'exclusion')
                    ->whereHas('user',  function($query) {
                        $query->where('user_id', user()->id); }) <-- user() defind in helper function for logged in user detail
                    ->whereHas('itenary', function($query) {
                        $query->where('tour_id', '21'); }) <-- pass tour id
                    ->whereHas('inclusion', function($query) {
                        $query->where('tour_id', '21'); }) <-- pass tour id
                    ->first();
解决方案

You can not do something like that on Laravel because the relationship is Has Many

You should do like this :

$tour = Tour::where('slug', $slug)
->whereHas('user',  function($query) {
    $query->where('user_id', user()->id);
}) <-- user() defind in helper function for logged in user detail
->whereHas('itenary', function($query) {
    $query->where('tour_id', '21');
}) <-- pass tour id
->whereHas('inclusion', function($query) {
    $query->where('tour_id', '21');
}) <-- pass tour id
->first();

$images = $tour->image;
$inclusions = $tour->inclusion;
$exclusions = $tour->exclusion;
$highlights = $tour->highlight;
$itenaries = $tour->itenary;

这篇关于哪里有多重关系 - laravel 5.4的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

10-11 09:03