本文介绍了MongoDB where子句的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有JSON格式的mongoDB"users"集合,我想返回所有具有保密性的数据.我该怎么办?
I have mongoDB "users" collection in JSON format and I want to return all the data having privacy is true. How can I do it ?
{
"name" : "Maria Kari",
"social" : [
{
"facebook" : "www.fb.com/maria.mongodb",
"privacy" : true
},
{
"twitter" : "www.tw.com/mongodb",
"privacy" : false
}
],
"personal" : [
{
"cell_no" : "+1-99082198414",
"privacy" : true
},
{
"email" : "maria@mongodb.com",
"privacy" : false
}
]
}
在这里,我想返回具有隐私权的数据.例如,facebook,它具有的隐私等于true.如何为此建立查询?
Here, I want to return the data having privacy is true. For example, facebook, it has privacy is equal to true. How to build query for this ?
谢谢. :')
推荐答案
db.users.find( {
$or:[{ 'social.privacy': true },{'personal.privacy': true}]
)
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