如何将 4 个 8 位坐标存储为一个整数(C#)?

通过这样做，我想创建一个字典，记录游戏中某些状态发生的频率.例如，5、10、20、12 是一种状态，6、10、20、12 是另一种状态.解决方案可以使用BitConverter从 4 个字节中获取一个整数:int i = BitConverter.ToInt32(new byte[] { player1X, player1Y, player2X, player2Y }, 0);从整数中取出四个字节:byte[]fourBytes = BitConverter.GetBytes(i);Lets say I have the following four variables: player1X, player1Y, player2X, player2Y. These have, for example, respectively the following values: 5, 10, 20, 12. Each of these values is 8 bits at max and I want to store them into one integer (32 bits), how can I achieve this?By doing this, I want to create a dictionary, keeping count of how often certain states have happened in the game. For example, 5, 10, 20, 12 is one state, 6, 10, 20, 12 would be another. 解决方案 You can use BitConverterTo get one Integer out of 4 bytes:int i = BitConverter.ToInt32(new byte[] { player1X, player1Y, player2X, player2Y }, 0);To get the four bytes out of the integer:byte[] fourBytes = BitConverter.GetBytes(i); 这篇关于如何将 4 个 8 位坐标存储为一个整数(C#)?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！ 上岸，阿里云！