python中有多个构造函数？

问题描述

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是否无法在Python中用不同的签名定义多个构造函数？如果不是，通常的解决方法是什么？

例如，假设您要定义一个 City

我想说 someCity = City（）或 someCity = City（ Berlin），第一个仅提供默认名称值，第二个定义默认值。

解决方案

与Java不同，您不能定义多个构造函数。但是，如果未传递默认值，则可以定义默认值。

  def __init __（self，city = Berlin）： 
 self.city =城市
  

Is it not possible to define multiple constructors in Python, with different signatures? If not, what's the general way of getting around it?

For example, let's say you wanted to define a class City

I'd like to be able to say someCity = City() or someCity = City("Berlin"), where the first just gives a default name value, and the second defines it.

解决方案

Unlike Java, you cannot define multiple constructors. However, you can define a default value if one is not passed.

def __init__(self, city="Berlin"):
  self.city = city

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