Java舍入到最近的.5

问题描述

这在Java中怎么可能？

How is this possible in Java?

我有一个浮点数，我想把它四舍五入到最接近的.5。

I have a float and I'd like to round it to the nearest .5.

例如：

1.1应该舍入到1.0

1.1 should round to 1.0

1.3应该舍入到1.5

1.3 should round to 1.5

2.5应该舍入到2.5

2.5 should round to 2.5

3.223920应该舍入到3.0

3.223920 should round to 3.0

编辑：另外，我不只是想要字符串表示，我想在之后使用实际的浮点数。

EDIT: Also, I don't just want the string representation, I want an actual float to work with after that.

解决方案

@SamiKorhonen在评论中说：

@SamiKorhonen said this in a comment:

所以这就是代码：

public static double roundToHalf(double d) {
    return Math.round(d * 2) / 2.0;
}

public static void main(String[] args) {
    double d1 = roundToHalf(1.1);
    double d2 = roundToHalf(1.3);
    double d3 = roundToHalf(2.5);
    double d4 = roundToHalf(3.223920);
    double d5 = roundToHalf(3);

    System.out.println(d1);
    System.out.println(d2);
    System.out.println(d3);
    System.out.println(d4);
    System.out.println(d5);
}

输出：

1.0
1.5
2.5
3.0
3.0

这篇关于Java舍入到最近的.5的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！