上传多个文件到服务器，并写入数据库

问题描述

所以目前我在我的html < input type =file中有以下代码required =requiredname =imagemultiple => $ b

然后在添加 mutliple =标签之前，这对我来说总是有效的， / b>

  if（isset（$ _ POST ['Submit']））
 {
 $ current_image = $ _ FILES [ '图像'] [ '名称']; 
 $ extension = substr（strrchr（$ current_image，'。'，1）; （（$ extension！=png）&&（$ extension！=jpg））
 {
 die（'Unknown extension'）; 
} 
 $ time = date（fYhis）; 
 $ new_image = $ time。  。 $扩展; 
 $ destination =./../ img / treatments /。new_image; 
 $ action = copy（$ _ FILES ['image'] ['tmp_name']，$ destination）; 
  

但是现在我试图上传多个文件，我想我需要添加一个数组来命名它们但我不明白，我不想更改我的代码非常多，如果我可以。

此刻img只是我的数据库中的一个字段，这个问题有多大？

编辑

代码，但似乎无法弄清楚如何实现它，并使其工作...

 <？php 
 / ** 
 *从$ _FILES数组中取出痛苦的类
 * @author Christiaan Baartse< [email protected]> 
 * / 
 class UploadedFiles extends ArrayObject 
 {
 public function current（）{
 return $ this-> _normalize（parent :: current（））; 
 
 
 public function offsetGet（$ offset）{
 return $ this-> _normalize（parent :: offsetGet（$ offset））; 
 
 
保护函数_normalize（$ entry）{
 if（isset（$ entry ['name']）&& is_array（$ entry ['name']] ））{
 $ files = array（）; 
 foreach（$ entry ['name'] as $ k => $ name）{
 $ files [$ k] = array（
'name'=> $ name，$ $ b'tmp_name'=> $ entry ['tmp_name'] [$ k]，
'size'=> $ entry ['size'] [$ k]，
'type' => $ entry ['type'] [$ k]，
'error'=> $ entry ['error'] [$ k] 
）; 
} 
返回新的自我（$文件）; 
} 
 return $ entry; 
} 
} 
？> 
  

 <？php 
 $ files = new UploadedFiles（$ _ FILES） ; 
 var_dump（$ files ['userfile'] ['christiaan'] [0] [0] ['is'] ['gaaf'] [0]）; 
 //或
 foreach（$ files ['userfile'] ['christiaan'] [0] [0] ['is'] ['gaaf'] as $ file）{
后续代码var_dump（$文件）; 
} 
？> 
  

解决方案

试试这个（你的问题似乎实际上是完全不知道如何在PHP中这一切工作，而不是一些具体的问题/错误/...): $ b $ p

whatever.php：

 < form enctype =multipart / form-dataaction =<？= $ _ SERVER ['PHP_SELF']？>> 
第一个文件：< input type =filename =uploads []/>< br> 
第二档案：< input type =filename =uploads []/>< br> 
一次多个文件（firefox，chrome，... not IE< 10）：< input type =filename =uploads_multiple []multiple =multiple/>< br> 
< input type =submitvalue =Go/> 
< / form> 
<？php 
 print_r（$ _ FILES）; 
  

尝试使用不同的输入（文件大小，缺少文件...）在PHP中。我认为，如果发布一些完成的代码，您将从中受益。

编辑：另外，不要使用副本！大多数情况下它不会工作，有时可能会带来意想不到的结果，有时候你只会打开一堆蠕虫。有一个原因move_uploaded_file存在 - 使用IT！

So at the moment I have the following code in my html <input type="file" required required="required" name="image" multiple="">

and then before I added the mutliple="" tag, this always worked for me,

if(isset($_POST['Submit']))
{
$current_image=$_FILES['image']['name'];
$extension = substr(strrchr($current_image, '.'), 1);
if (($extension!= "png") && ($extension != "jpg"))
{
die('Unknown extension');
}
$time = date("fYhis");
$new_image = $time . "." . $extension;
$destination="./../img/treatments/".$new_image;
$action = copy($_FILES['image']['tmp_name'], $destination);

but now that i am trying to upload multiple files I think I need to add an array to name them but I cannot figure it out, I don't want to change my code very much if I can.

Also at the moment the img is only one field on my database, how much of an issue is this?

EDIT

I found this code but cant seem to figure out how to implement it and make it work...

<?php
/**
 * A class that takes the pain out of the $_FILES array
 * @author Christiaan Baartse <[email protected]>
 */
class UploadedFiles extends ArrayObject
{
    public function current() {
        return $this->_normalize(parent::current());
    }

    public function offsetGet($offset) {
        return $this->_normalize(parent::offsetGet($offset));
    }

    protected function _normalize($entry) {
        if(isset($entry['name']) && is_array($entry['name'])) {
            $files = array();
            foreach($entry['name'] as $k => $name) {
                $files[$k] = array(
                    'name' => $name,
                    'tmp_name' => $entry['tmp_name'][$k],
                    'size' => $entry['size'][$k],
                    'type' => $entry['type'][$k],
                    'error' => $entry['error'][$k]
                );
            }
            return new self($files);
        }
        return $entry;
    }
    }
    ?>

<?php
$files = new UploadedFiles($_FILES);
var_dump($files['userfile']['christiaan'][0][0]['is']['gaaf'][0]);
// or
foreach($files['userfile']['christiaan'][0][0]['is']['gaaf'] as $file) {
    var_dump($file);
}
?>

解决方案

Try this (your problem seems in fact to be the totally missing understanding of how this all works in php, instead of some specific problem/bug/...):

whatever.php:

<form enctype="multipart/form-data" action="<?=$_SERVER['PHP_SELF']?>">
First file: <input type="file" name="uploads[]" /><br>
Second File: <input type="file" name="uploads[]" /><br>
Multiple files at once (firefox, chrome, ... not IE < 10): <input type="file" name="uploads_multiple[]" multiple="multiple" /><br>
<input type="submit" value="Go" />
</form>
<?php
print_r($_FILES);

Try this with different inputs (filesizes, missing files, ...) to see what you get from that in php. I think you'll benefit from this way more than if posted some finished code.

Edit: Also, DON'T use copy for this! Most of the time it just won't work, sometimes it might give unexpected results, and sometimes you'll just be opening a can of worms. There is a reason the function move_uploaded_file exists - USE IT!

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