如何根据gridview值启用按钮？ | 如何根据gridview值启用按钮

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问题描述

I have a column in SQL:

Status
open
Close

and Gridview with Boundfield value='Status'

When a user selects a row and the Status == open then it should display a button. Otherwise ist hiden.

我尝试过：

What I have tried:

protected void GridView1_SelectedIndexChanged(object sender, EventArgs e)
    {


        string y = Data.Rows[GridView1.SelectedIndex][5].ToString();


        if (y == "open")
        {
           btnAccept.Visible = true;
        }
        else
        {
            btnAccept.Visible = false;
        }
    }

推荐答案

 //  I think you should hide show the button on gridview_rowdatabound event like this.

       //look this is just the pseudo code
        //put the button you want to show/hide in the template field of gridview and try to find the control in the below event [OnRowDataBound]
        protected void gridview1_rowdatabound(object sender, GridViewRowEventArgs e)
        {
            //find the button control
            Button btnStatus = (Button)Gridview1.FindControl("yourControlName");
            foreach (GridViewRow gvrow in Gridview1.Rows)
            {
                // now read the status column value and enable/disable the button
                string status = gvrow.Column[yourColumnIndexStartingFrom 0].Text;
                if (status == "Open")
                { btnStatus.Visible = true; }
                else
                { btnStatus.Visible = false; }

            }
        }
// Let me know if it helps or not

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