问题描述
我正尝试在laravel中发出一个http发帖请求
I am trying to make a http post request in laravel as below
$client = new Client(['debug'=>true,'exceptions'=>false]);
$res = $client->request('POST', 'http://www.myservice.com/find_provider.php', [
'form_params' => [
'street'=> 'test',
'apt'=> '',
'zip'=> 'test',
'phone'=> 'test',
]
]);
返回空响应.调试时,发生以下异常
It return empty response. On debugging ,following exception is occurring
curl_setopt_array():不能将输出类型的流表示为STDIO FILE *
curl_setopt_array(): cannot represent a stream of type Output as a STDIO FILE*
我正在使用最新版本的guzzle.
I am using latest version of guzzle.
有什么想法要解决吗?.
Any idea how to solve it?.
推荐答案
request()方法将返回 GuzzleHttp \ Psr7 \ Response 对象.要获取服务返回的实际数据,您应该使用:
The request() method is returning a GuzzleHttp\Psr7\Response object.To get the actual data that is returned by your service you should use:
$data = $res->getBody()->getContents();
现在检查$ data中的内容以及它是否与预期的输出相对应.
Now check what you have in $data and if it corresponds to the expected output.
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