问题描述
这是我老师的分配，但我认为在''正常'的条款中意味着：
写一个带RGB（r，g，b）的函数; r，g和b是0到31之间的值;然后它将其转换为16位RGB。
我不知道该怎么做，或者它意味着什么。
提前谢谢。
That''s the assigment from my teacher, but i think in ''normal'' terms that means:
Write a function that takes RGB(r,g,b); r, g and b being values between 0 and 31; it then converts it to 16 bit RGB.
I haven''t a clue how to do that, or what it means.
Thanks in advance.
推荐答案
请注意，[0,31]范围内的值占用5位。其中三个旁边每个
其他占15位。这非常适合16位字。看看位移
运算符<<和>>
亲切的问候，
Jos
Note that a value in the range [0, 31] takes up 5 bits. Three of them next to each
other take up 15 bits. That fits nicely in a 16 bit word. Have a look at the bit shift
operators << and >>
kind regards,
Jos
那个对我来说并不是很重要。我没有做太多的比特，比特移位等。
That doesn''t really mean much to me. I haven''t done much with bits, bit shift etc..
嗯：开始阅读。
kind问候，
Jos
Well: start reading then.
kind regards,
Jos
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