本文介绍了试图在 Yii 中获取非对象错误的属性的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
案例 1:我得到一个 CActiveRecords 数组并尝试循环遍历它,如下所示:
Case 1: I get an array of CActiveRecords and try to loop over it as shown below:
foreach ($pendingTasks as $task)
{
if($task->task->employee_id=="1")
{
//some logic here
}
}
我得到试图获取非对象的属性"
I get "Trying to get property of non-object "
案例 2:如果我尝试:
Case 2: If I try:
$pendingTasks = TaskLog::model()->findByPk("1");
if($pendingTasks->task->employee_id=="1")
{
//some logic here
}
这有效.为什么会这样?我在这里做错了什么吗?
This works.Why is this so? Am I doing any thing wrong here?
推荐答案
因为 $pendingTasks
中的 tasks
不能有关系.您可以通过简单地添加一个 isset()
来检查:
Because of the tasks
in $pendingTasks
must not have a relation. You can check by simply adding an isset()
like so:
foreach ($pendingTasks as $task) {
if(isset($task->task) && $task->task->employee_id=="1") {
//some logic here
} else {
echo "{$task->id} doesn't have a task relation";
}
}
假设 $pendingTasks
也是 TaskLog
的实例.
Assuming $pendingTasks
are instances of TaskLog
also.
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