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问题描述
我似乎无法使此嵌套的for循环正常工作，我想用EP名称和其他详细信息在该行中的EP上打印所有轨道.第一个for-each循环中的所有内容都可以正确显示，但是for-each循环中没有任何内容可以获取曲目.
I cant seem to get this nested for loop to work correctly, I want to print all of the tracks on the EP in the row with the EP name and other details. Everything from the first for-each loop displays correctly but nothing is pulled through for the for-each loop to get the tracks.
这是我的XML
<dalehoward>
<ep>
<name>Letters EP</name>
<year>2012</year>
<label>Static Audio</label>
<image>letters.jpg</image>
<tracks>
<track number="1">
<tname>Letters</tname>
<length>6.35</length>
</track>
<track number="2">
<tname>Later</tname>
<length>7.56</length>
</track>
<track number="3">
<tname>'89 Flava</tname>
<length>7:38</length>
</track>
<track number="4">
<tname>Safe Presentation</tname>
<length>7.55</length>
</track>
</tracks>
</ep>
<ep>
<name>Inner City EP</name>
<year>2012</year>
<label>Lost My Dog</label>
<image>innercity.jpg</image>
<tracks>
<track number="1">
<tname>C'Mon</tname>
<length>7.15</length>
</track>
<track number="2">
<tname>Koppabird</tname>
<length>6.27</length>
</track>
<track number="3">
<tname>Inner City</tname>
<length>8:50</length>
</track>
<track number="4">
<tname>You Can</tname>
<length>8:16</length>
</track>
<tracks>
</ep>
<dalehoward>
这是XSLT
<xsl:variable name="imagefolder" select="'xml/images/'" />
<xsl:template match="/">
<html>
<body>
<h2>My CD Collection</h2>
<table border="1" width="100%">
<tr bgcolor="#9acd32">
<th style="text-align:left">Title</th>
<th style="text-align:left">Year</th>
<th style="text-align:left">Label</th>
<th style="text-align:left">Tracks</th>
<th style="text-align:left">Artwork</th>
</tr>
<xsl:for-each select="dalehoward/ep">
<tr>
<td><xsl:value-of select="name"/></td>
<td><xsl:value-of select="year"/></td>
<td><xsl:value-of select="label"/></td>
<td>testtext<xsl:for-each select="dalehoward/ep/tracks">
<xsl:value-of select="tname"/><br />
<xsl:value-of select="length"/> <br /><br />
</xsl:for-each></td>
<td><img width="150px" height="150px"><xsl:attribute name="src">
<xsl:copy-of select="$imagefolder"/>
<xsl:value-of select="image"/>
</xsl:attribute></img></td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
非常感谢您的帮助
推荐答案
外部循环将您置于ep的上下文中.需要从那里建立内部循环的上下文(或从根开始作为绝对路径)-因此，请更改:
The outer loop puts you in the context of ep. The context of the inner loop needs to be established from there (or as an absolute path, starting from the root) - so change:
<xsl:for-each select="dalehoward/ep/tracks">
收件人:
<xsl:for-each select="tracks/track">
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