在pgpy中解密失败，并显示"ValueError:预期:ASCII装甲的PGP数据".

问题描述

我在文本文件中有一个OpenPGP加密文件及其私钥，并且知道其密码短语.

I have an OpenPGP encrypted file and its private key in a text file and know its passphrase.

我尝试了以下代码:

import pgpy

emsg = pgpy.PGPMessage.from_file('PGPEcrypted.txt')
key,_  = pgpy.PGPKey.from_file('PrivateKey.txt')
with key.unlock('passcode!'):
    print (key.decrypt(emsg).message)

但是在尝试执行时，出现以下错误:

But while trying to execute I am getting following error:

Traceback (most recent call last):
  File "D:\Project\PGP\pgp_test.py", line 4, in <module>
    key,_  = pgpy.PGPKey.from_file('SyngentaPrivateKey.txt')
  File "D:\Anaconda\lib\site-packages\pgpy\types.py", line 191, in from_file
    po = obj.parse(data)
  File "D:\Anaconda\lib\site-packages\pgpy\pgp.py", line 2252, in parse
    unarmored = self.ascii_unarmor(data)
  File "D:\Anaconda\lib\site-packages\pgpy\types.py", line 131, in ascii_unarmor
    raise ValueError("Expected: ASCII-armored PGP data")
ValueError: Expected: ASCII-armored PGP data

如何在python中解密文件?

How can I decrypt the file in python?

推荐答案

OpenPGP知道两种消息格式:二进制编码(更节省空间)和类似于base64的ASCII装甲(特别是与旧的Internet协议兼容). pgpy.from_file 仅加载ASCII铠装消息.如果您使用的是二进制格式的消息，请改用 pgpy.from_blob .从 pgpy 文档:

OpenPGP knows two message formats: the binary encoding (more space-efficient) and the base64-like ASCII-armoring (better compatibility especially with old internet protocols). pgpy.from_file only loads ASCII armored messages. If you've messages in the binary format, use pgpy.from_blob instead. From the pgpy documentation:

# PGPMessage will automatically determine if this is a cleartext message or not
message_from_file = pgpy.PGPMessage.from_file("path/to/a/message")
message_from_blob = pgpy.PGPMessage.from_blob(msg_blob)

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