jQuery 在元素滚动离开页面时淡出元素，在它们向回滚动时淡出

问题描述

我希望元素在从页面顶部滚动时淡出，然后在它们回滚到页面上时淡入.我写了一些有效的代码，但我正在寻找更优雅的解决方案.这是我在 jsfiddle 上的解决方案:http://jsfiddle.net/wmmead/JdbhV/3/

我想找到一段更短、更优雅的代码，但无法完全解决.也许有一个数组和 each() 方法?如果我在 div 上放一个类而不是一个 ID，它会变得更短，但它们会同时淡出.我希望每个框在滚动离开页面时淡出.

HTML

<div id="box2"></div><div id="box3"></div><div id="box4"></div><div id="box5"></div><div id="box6"></div>

CSS

#box1, #box2, #box3, #box4, #box5, #box6 {宽度:100px；高度:100px；背景:橙色；边距:100px 自动；}#box6 {底边距:600px；}

jQuery

var box1Top = $('#box1').offset().top;var box2Top = $('#box2').offset().top;var box3Top = $('#box3').offset().top;var box4Top = $('#box4').offset().top;var box5Top = $('#box5').offset().top;var box6Top = $('#box6').offset().top;$(窗口).滚动(功能(){如果 ((box1Top - $(window).scrollTop()) 

解决方案

你可以使用属性选择器 '[attr="someattr"]' 和 .each() jQuery 的方法:

$(window).scroll(function () {$('[id^=box"]').each(function () {//<---循环 div id 以 #box 开头if ((($(this).offset().top - $(window).scrollTop()) < 20) {//<---标记当前对象的$(this).offset().top$(this).stop().fadeTo(100, 0);//<----淡出当前对象} 别的 {$(this).stop().fadeTo('fast', 1);//<----淡入当前对象}});});

您可以在这里进行演示:

演示

I want elements to fade out as they scroll off the top of the page, and then fade back in as they scroll back onto the page. I wrote some code that works, but I am looking for a more elegant solution. Here is the solution I have working on jsfiddle: http://jsfiddle.net/wmmead/JdbhV/3/

I would like to find a much shorter, more elegant piece of code, but just can't quite work it out. Maybe something with an array and the each() method? If I put a class on the divs instead of an ID, it gets a lot shorter, but then they all fade out at once. I want each box to fade out as it scrolls off the page.

HTML

<div id="box1"></div>
<div id="box2"></div>
<div id="box3"></div>
<div id="box4"></div>
<div id="box5"></div>
<div id="box6"></div>

CSS

#box1, #box2, #box3, #box4, #box5, #box6 {
  width: 100px;
  height: 100px;
  background: orange;
  margin:100px auto;
}
#box6 {
  margin-bottom:600px;
}

jQuery

var box1Top = $('#box1').offset().top;
var box2Top = $('#box2').offset().top;
var box3Top = $('#box3').offset().top;
var box4Top = $('#box4').offset().top;
var box5Top = $('#box5').offset().top;
var box6Top = $('#box6').offset().top;

$(window).scroll(function () {
if ((box1Top - $(window).scrollTop()) < 20) {
    $('#box1').stop().fadeTo(100, 0);
} else {
    $('#box1').stop().fadeTo('fast', 1);
}

if ((box2Top - $(window).scrollTop()) < 20) {
    $('#box2').stop().fadeTo(100, 0);
} else {
    $('#box2').stop().fadeTo('fast', 1);
}

if ((box3Top - $(window).scrollTop()) < 20) {
    $('#box3').stop().fadeTo(100, 0);
} else {
    $('#box3').stop().fadeTo('fast', 1);
}

if ((box4Top - $(window).scrollTop()) < 20) {
    $('#box4').stop().fadeTo(100, 0);
} else {
    $('#box4').stop().fadeTo('fast', 1);
}

if ((box5Top - $(window).scrollTop()) < 20) {
    $('#box5').stop().fadeTo(100, 0);
} else {
    $('#box5').stop().fadeTo('fast', 1);
}
if ((box6Top - $(window).scrollTop()) < 20) {
    $('#box6').stop().fadeTo(100, 0);
} else {
    $('#box6').stop().fadeTo('fast', 1);
}
});

解决方案

You can use attribute selector '[attr="someattr"]' with use of .each() method of jQuery:

$(window).scroll(function () {
   $('[id^="box"]').each(function () { // <---loop the divs id starts with #box
      if (($(this).offset().top - $(window).scrollTop()) < 20) { //<---mark the $(this).offset().top of current object
          $(this).stop().fadeTo(100, 0); //<----fadeOut the current obj
      } else {
          $(this).stop().fadeTo('fast', 1); //<----fadeIn the current obj
      }
   });
});

You can take a demo here:

DEMO

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