本文介绍了JavaScript函数参数不起作用的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我读过的每个站点都说,如果声明了一个函数,它将只带有一个参数,但是我不能在这里使用它.

Every site I've read says a function would just take a parameter if you declare it, however I can't get it to work here.

像这样工作:

    <script type='text/javascript'>
    function trackSubmit() {
        setTimeout(function(){
            ga('send', 'event', 'category', 'action', 'link', 4);
        }, 100);
     }
</script>

并且:

<form onsubmit="trackSubmit()">

但是,如果我尝试这样的操作,它将无法正常工作.

However, if I try something like this, it doesn't work.

    <script type='text/javascript'>
    function trackSubmit(category, action, link) {
        setTimeout(function(){
            ga('send', 'event', category, action, link, 4);
        }, 100);
     }
</script>

<form onsubmit="trackSubmit(testcategory, testaction, testlink)">

我该怎么做才能解决此问题?还是应该只具有多个功能,例如trackSubmit1,trackSubmit2等?虽然那不是很方便.

What can I do to fix this? Or should I just have multiple functions like trackSubmit1, trackSubmit2, etc? Though that wouldn't be very convenient.

谢谢您的帮助.

推荐答案

您需要使用qoutation<form onsubmit="trackSubmit('testcategory', 'testaction', 'testlink')">如果有变量,则需要像\''+ testcategory +'\'那样串联...

you need to use qoutation<form onsubmit="trackSubmit('testcategory', 'testaction', 'testlink')">if there are variable then need to concatenate like \''+testcategory+'\' , ...

这篇关于JavaScript函数参数不起作用的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

07-13 02:15