订阅者可以充当发布者吗?

问题描述

就反应式流而言，有一个发布者，它可以有尽可能多的订阅者.

In terms of Reactive Streams, there is a Publisher and it could have as many Subscribers.

但是，假设订阅者从发布者那里收到一条消息.现在，此订户(例如Subs1)更改/修改了该消息，并将其传递给其他订户(例如Subs2)，后者使用了已修改的消息.

But suppose, a subscriber gets a message from Publisher. Now this Subscriber(say Subs1) changes/modifies the message and passes it to some other Subscriber(say Subs2), which consumes the modified message.

那么，这个Subs1订阅者可以充当发布者，该发布者可以将消息传递给新的Subs2订阅者吗?

So can this Subs1 subscriber can act as a Publisher which can pass on message to new Subs2 subscriber?

我不确定是否可以，但是我认为这种情况是可能的.

I am not sure if it possible or not, but the scenario is possible i think.

如果可能，请提出一个可行的方法.

If its possible, please suggest a possible way to do this.

推荐答案

这是完成此操作的完整实现:​​

Here is the complete implementation to do this:

1. 创建一个MyTransformer类，该类实现Processor并扩展SubmissionPublisher，因为它将同时充当Subscriber和Publisher:

1. Create a MyTransformer class which implements Processor and extends SubmissionPublisher, as it will act both as Subscriber and Publisher:

import java.util.concurrent.Flow;
import java.util.concurrent.Flow.Subscription;
import java.util.concurrent.SubmissionPublisher;
import java.util.function.Function;

public class MyTransformer<T, R> extends SubmissionPublisher<R> implements Flow.Processor<T, R> {

private Function<T, R> function;
private Flow.Subscription subscription;

public MyTransformer(Function<T, R> function) {
    super();
    this.function = function;
}

@Override
public void onComplete() {
    System.out.println("Transformer Completed");
}

@Override
public void onError(Throwable e) {
    e.printStackTrace();
}

@Override
public void onNext(T item) {
    System.out.println("Transformer Got : "+item);
    submit(function.apply(item));
    subscription.request(1);

}

@Override
public void onSubscribe(Subscription subscription) {
    this.subscription = subscription;
    subscription.request(1);
}



}

创建一个TestSubscriber类，该类实现Subscriber接口并实现所需的方法:

Create an TestSubscriber class which implements the Subscriber interface and implement the required methods:

在处理开始之前调用onSubscribe()方法.订阅的实例作为参数传递.这是一个类，用于控制订阅服务器和发布服务器之间的消息流.

The onSubscribe() method is called before processing starts. The instance of the Subscription is passed as the argument. It is a class that is used to control the flow of messages between Subscriber and the Publisher.

这里的主要方法是onNext()－每当发布者发布新消息时都会调用此方法.

The main method here is onNext() – this is called whenever the Publisher publishes a new message.

我们正在使用实现Publisher接口的SubmissionPublisher类.

We are using the SubmissionPublisher class which implements the Publisher interface.

我们将向发布者提交N个元素-我们的TestSubscriber将接收该元素.

We’re going to be submitting N elements to the Publisher – which our TestSubscriber will be receiving.

请注意，我们正在TestSubscriber实例上调用close()方法.它将在给定发布者的每个订阅者下面调用onComplete()回调.

Note, that we’re calling the close() method on the instance of the TestSubscriber. It will invoke onComplete() callback underneath on every Subscriber of the given Publisher.

import java.util.LinkedList;
import java.util.List;
import java.util.concurrent.Flow.Subscriber;
import java.util.concurrent.Flow.Subscription;

public class TestSubscriber<T> implements Subscriber<T> {

    private Subscription subscription;

    public List<T> consumed = new LinkedList<>();

    @Override
    public void onComplete() {
        System.out.println("Subsciber Completed");
    }

    @Override
    public void onError(Throwable arg0) {
        arg0.printStackTrace();
    }

    @Override
    public void onNext(T item) {
        System.out.println("In Subscriber Got : "+item);
        subscription.request(1);

    }

    @Override
    public void onSubscribe(Subscription subscription) {
        this.subscription = subscription;
        subscription.request(1);
    }

}

1. 这里是发布者正在发布String元素的处理流程.

MyTransformer正在将String解析为Integer，这意味着此处需要进行转换.

MyTransformer is parsing the String as Integer – which means a conversion needs to happening here.

import java.util.List;
import java.util.concurrent.SubmissionPublisher;;

public class TestTransformer {

    public static void main(String... args) {
        SubmissionPublisher<String> publisher = new SubmissionPublisher<>();
        MyTransformer<String, Integer> transformProcessor = new MyTransformer<>(Integer::parseInt);

        TestSubscriber<Integer> subscriber = new TestSubscriber<>();
        List<String> items = List.of("1", "2", "3");

        List<Integer> expectedResult = List.of(1, 2, 3);

        publisher.subscribe(transformProcessor);
        transformProcessor.subscribe(subscriber);
        items.forEach(publisher::submit);
        publisher.close();

    }
}

这篇关于订阅者可以充当发布者吗?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！