本文介绍了安卓得到ArrayList中的所有联系人的电话号码的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我想保存的所有联系人的电话号码在一个ArrayList但我不能找到一种方法如何。有没有办法让他们,而不是挑选他们一个个ContactsContract?
解决方案
ContentResolver的CR = mContext.getContentResolver(); //活动/应用android.content.Context
光标光标= cr.query(ContactsContract.Contacts.CONTENT_URI,NULL,NULL,NULL,NULL);
如果(cursor.moveToFirst())
{
ArrayList的<字符串> alContacts =新的ArrayList<字符串>();
做
{
字符串ID = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts._ID));
if(Integer.parseInt(cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0)
{
光标pCur = cr.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,null,ContactsContract.CommonDataKinds.Phone.CONTACT_ID +=?,新的String [] {ID},NULL);
而(pCur.moveToNext())
{
串contactNumber = pCur.getString(pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
alContacts.add(contactNumber);
打破;
}
pCur.close();
}
}而(cursor.moveToNext());
}
I am trying to save all contacts telephone numbers in an ArrayList but I cant find a way how. Is there a way to get them instead of picking them one by one with ContactsContract?
解决方案
ContentResolver cr = mContext.getContentResolver(); //Activity/Application android.content.Context
Cursor cursor = cr.query(ContactsContract.Contacts.CONTENT_URI, null, null, null, null);
if(cursor.moveToFirst())
{
ArrayList<String> alContacts = new ArrayList<String>();
do
{
String id = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts._ID));
if(Integer.parseInt(cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0)
{
Cursor pCur = cr.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,null,ContactsContract.CommonDataKinds.Phone.CONTACT_ID +" = ?",new String[]{ id }, null);
while (pCur.moveToNext())
{
String contactNumber = pCur.getString(pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
alContacts.add(contactNumber);
break;
}
pCur.close();
}
} while (cursor.moveToNext()) ;
}
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