本文介绍了读/从Android的通讯录只能解析手机号码（ContactsContract.Contacts）的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
如何从机器人电话簿得到所有真正的手机号码？
我用ContactsContract.Contacts，创造各自的游标。
而它的做工精细，
我stuckup只取有效的手机号码
我们可以使用ContactsContract.CommonDataKinds.Phone.TYPE_MOBILE过滤手机号码，
但我们也可以节约有效的手机号码到像ContactsContract.CommonDataKinds.Phone.TYPE_HOME等领域反之亦然
字符串phoneNumber的= NULL;
字符串email = NULL; 乌里CONTENT_URI = ContactsContract.Contacts.CONTENT_URI;
字符串_ID = ContactsContract.Contacts._ID;
字符串DISPLAY_NAME = ContactsContract.Contacts.DISPLAY_NAME;
字符串HAS_PHONE_NUMBER = ContactsContract.Contacts.HAS_PHONE_NUMBER; 乌里PhoneCONTENT_URI = ContactsContract.CommonDataKinds.Phone.CONTENT_URI;
字符串Phone_CONTACT_ID = ContactsContract.CommonDataKinds.Phone.CONTACT_ID;
串号= ContactsContract.CommonDataKinds.Phone.NUMBER; StringBuffer的输出=新的StringBuffer（）; ContentResolver的ContentResolver的= getContentResolver（）; 光标光标= contentResolver.query（CONTENT_URI，NULL，NULL，NULL，NULL）; //循环手机中的每一个接触
如果（cursor.getCount（）大于0）{
Log.d（：，算:::+ cursor.getCount（））; 而（cursor.moveToNext（））{ 串CONTACT_ID = cursor.getString（cursor.getColumnIndex（_ID））;
字符串名称= cursor.getString（cursor.getColumnIndex（DISPLAY_NAME））; INT hasPhoneNumber =的Integer.parseInt（cursor.getString（cursor.getColumnIndex（HAS_PHONE_NUMBER）））; 如果（hasPhoneNumber大于0）{ output.append（\\ n名字：+姓名）; //查询及回路接触的每一个电话号码
光标phoneCursor = contentResolver.query（PhoneCONTENT_URI，空，Phone_CONTACT_ID +=？，新的String [] {} CONTACT_ID，NULL）; 而（phoneCursor.moveToNext（））{
phoneNumber的= phoneCursor.getString（phoneCursor.getColumnIndex（NUMBER））;
//串号= phones.getString（phones.getColumnIndex（ContactsContract.CommonDataKinds.Phone.NUMBER））;
整型= phoneCursor.getInt（phoneCursor.getColumnIndex（ContactsContract.CommonDataKinds.Phone.TYPE））;
开关（类型）{
案例ContactsContract.CommonDataKinds.Phone.TYPE_HOME：
//做这里的家庭号码的东西...
打破;
案例ContactsContract.CommonDataKinds.Phone.TYPE_MOBILE：
output.append（\\ n电话号码：+ phoneNumber的）;
打破;
案例ContactsContract.CommonDataKinds.Phone.TYPE_WORK：
//做这里的工作数量的东西...
打破;
}
}
/ *
而（phoneCursor.moveToNext（））{
phoneNumber的= phoneCursor.getString（phoneCursor.getColumnIndex（NUMBER））;
output.append（\\ n电话号码：+ phoneNumber的）;
}
* / phoneCursor.close（）;
} output.append（\\ n）;
} outputText.setText（输出）;
}
解决方案
这个功能在使用Android的某些pre-codeD的东西，像Patterns.PHONE.matcher ......这可能是有用的：
//如果电话号码是有效的，则返回true
私人布尔isValidPhoneNumber（CharSequence的phoneNumber的）{
返回TextUtils.isEmpty（phoneNumber的）及！＆安培; Patterns.PHONE.matcher（phoneNumber的）.matches（）;
}
How to get all the real mobile numbers from androids phone book?
I used ContactsContract.Contacts and created respective cursors.while it's working fine, I am stuckup with only fetching VALID MOBILE NUMBERS
We can use ContactsContract.CommonDataKinds.Phone.TYPE_MOBILE to filter Mobile Numbers,but we can also save valid mobile numbers into other fields like ContactsContract.CommonDataKinds.Phone.TYPE_HOME and vice versa
String phoneNumber = null;
String email = null;
Uri CONTENT_URI = ContactsContract.Contacts.CONTENT_URI;
String _ID = ContactsContract.Contacts._ID;
String DISPLAY_NAME = ContactsContract.Contacts.DISPLAY_NAME;
String HAS_PHONE_NUMBER = ContactsContract.Contacts.HAS_PHONE_NUMBER;
Uri PhoneCONTENT_URI = ContactsContract.CommonDataKinds.Phone.CONTENT_URI;
String Phone_CONTACT_ID = ContactsContract.CommonDataKinds.Phone.CONTACT_ID;
String NUMBER = ContactsContract.CommonDataKinds.Phone.NUMBER;
StringBuffer output = new StringBuffer();
ContentResolver contentResolver = getContentResolver();
Cursor cursor = contentResolver.query(CONTENT_URI, null, null, null, null);
// Loop for every contact in the phone
if (cursor.getCount() > 0) {
Log.d(": ", "count ::: " + cursor.getCount());
while (cursor.moveToNext()) {
String contact_id = cursor.getString(cursor.getColumnIndex(_ID));
String name = cursor.getString(cursor.getColumnIndex(DISPLAY_NAME));
int hasPhoneNumber = Integer.parseInt(cursor.getString(cursor.getColumnIndex(HAS_PHONE_NUMBER)));
if (hasPhoneNumber > 0) {
output.append("\n First Name:" + name);
// Query and loop for every phone number of the contact
Cursor phoneCursor = contentResolver.query(PhoneCONTENT_URI, null, Phone_CONTACT_ID + " = ?", new String[]{contact_id}, null);
while (phoneCursor.moveToNext()) {
phoneNumber = phoneCursor.getString(phoneCursor.getColumnIndex(NUMBER));
//String number = phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
int type = phoneCursor.getInt(phoneCursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.TYPE));
switch (type) {
case ContactsContract.CommonDataKinds.Phone.TYPE_HOME:
// do something with the Home number here...
break;
case ContactsContract.CommonDataKinds.Phone.TYPE_MOBILE:
output.append("\n Phone number:" + phoneNumber);
break;
case ContactsContract.CommonDataKinds.Phone.TYPE_WORK:
// do something with the Work number here...
break;
}
}
/*
while (phoneCursor.moveToNext()) {
phoneNumber = phoneCursor.getString(phoneCursor.getColumnIndex(NUMBER));
output.append("\n Phone number:" + phoneNumber);
}
*/
phoneCursor.close();
}
output.append("\n");
}
outputText.setText(output);
}
解决方案
This function uses some pre-coded stuff in Android, like the Patterns.PHONE.matcher... This might be useful:
//Returns true if phone number is valid
private boolean isValidPhoneNumber(CharSequence phoneNumber) {
return !TextUtils.isEmpty(phoneNumber) && Patterns.PHONE.matcher(phoneNumber).matches();
}
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