本文介绍了Java 8 Lambda从对象列表创建字符串列表的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有以下问题:
如何将以下代码片段转换为Java 8 lambda样式?
How can I convert the following code snipped to Java 8 lambda style?
List<String> tmpAdresses = new ArrayList<String>();
for (User user : users) {
tmpAdresses.add(user.getAdress());
}
不知道,从以下内容开始:
Have no idea and started with the following:
List<String> tmpAdresses = users.stream().map((User user) -> user.getAdress());
推荐答案
您需要collect
您的流进入列表:
You need to collect
your stream into a List:
List<String> adresses = users.stream()
.map(User::getAdress)
.collect(Collectors.toList());
有关其他Collectors
的更多信息,请访问文档
For more information on the different Collectors
visit the documentation
User::getAdress
只是编写(User user) -> user.getAdress()
的另一种形式,也可以写为user -> user.getAdress()
(因为类型User
将由编译器推断)
User::getAdress
is just another form of writing (User user) -> user.getAdress()
which could aswell be written as user -> user.getAdress()
(because the type User
will be inferred by the compiler)
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