本文介绍了酶wrapper.find(..)。模拟按键不会触发事件监听器的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试在其中一个输入框上按 enter (输入)。手动执行此操作会触发事件侦听器,但是,在尝试使用酶时,不会触发事件侦听器。我在这里做什么错了?
I am trying to press enter on one of the input boxes. Doing it manually triggers the event listener, however, while trying with enzyme, the event listener is not triggered. What am I doing wrong here?
this.input.addEventListener('keypress', function(event){
debugger;
onEnter(event);
});
function setup(store, props) {
return mount(<Provider store={store}>
<component{...props}/>
</Provider>
);
}
beforeEach(() => {
wrapper = setup(store, {});
searchBar = wrapper.find('searchBar');
searchInput = searchBar.find("input");
});
it("when enter is pressed, event should be triggered", ()=> {
let wait = false;
runs(()=> {
searchInput.simulate('change', {target: {value: 'helloWorld'}});
searchInput.simulate('keyPress', {which: 13});
setTimeout(()=> {
wait = true;
}, 1000);
})
waitsFor(()=> {
return wait;
}, "", 1500);
})
推荐答案
我也在努力解决这个问题。但是现在我找到了解决方案。
除了 {其中:13}
参数之外,您还需要至少指定 key
参数,因此您的模拟表达式将如下所示:
I was struggling with this problem too. But now I`ve found a solution.In addition to { which: 13 }
parameter, you need to specify at least key
parameter, so your simulate expression will be like:
searchInput.simulate('keyPress', {
key: 'Enter',
keyCode: 13,
which: 13,
});
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