调整图像的宽度和高度

问题描述

我的内容存储在mysql中，如下所示：

< table width =210cellspacing =1cellpadding =1border =0> 
< tbody> 
< tr> 
< td>< img width =513height =680align =leftalt =src =/ userfiles / image / pic.jpg/>< / td> 
< td>< img width =315height =700align =leftalt =src =/ userfiles / image / DSC_0389.JPG/>< / td> 
< td>< img width =580height =320align =leftalt =src =/ userfiles / image / ktxh.jpg/>< / td> 
< / tr> 
< / tbody> 
< / table> 

当我从中加载时db，PHP和PHP在html中显示，没有问题。 
 
从mysql（$ child_article [6]）读取的$ content并通过动态代码以html显示：
 
 $ sql_article =select * from articles approved = 1个按时间顺序DESC的顺序; @ $ childResult_article = general_query（$ sql_article）; 
 if（$ child_article = mysql_fetch_row（$ childResult_article））
 echo decode_data（$ child_article [6]）。 
 
 
现在，我想要所有图像，以固定的宽度和高度显示为200 X 200 AND TABLE BORDER ='0'（通过php从mysql加载$ content并替换宽度和高度所有图像按200 x 200然后回显$ content到网站）

我尝试过：

我试过，但不能结果：
 
 $ newWidth = 200; 
 $ newHeight = 200; 
 $ content = preg_replace（array（'/ width =\d +/ i'，'/ height =\d +/ i'），array（sprintf（'width =％d' ，$ newWidth），sprintf（'height =％d'，$ newHeight）），$ child_article [6]）; 

我如何解决这个问题？

解决方案

I have content stored in mysql, as following: 

<table width="210" cellspacing="1" cellpadding="1" border="0">
    <tbody>
        <tr>
            <td><img width="513" height="680" align="left" alt="" src="/userfiles/image/pic.jpg" /></td>
            <td><img width="315" height="700" align="left" alt="" src="/userfiles/image/DSC_0389.JPG" /></td>
            <td><img width="580" height="320" align="left" alt="" src="/userfiles/image/ktxh.jpg" /></td>
        </tr>
    </tbody>
</table>

When I load from db, PHP and display in html by PHP, there is no problem.

The $content it be read from mysql($child_article[6]) and display in html by dynamic code:

$sql_article = "select * from articles where approved=1 order by timestamp DESC"; @$childResult_article = general_query($sql_article);
if ($child_article = mysql_fetch_row($childResult_article))
echo decode_data($child_article[6]).


Now, I want all images, be displayed by fixed width and height as 200 X 200 AND TABLE BORDER = '0' ($content load from mysql by php and replace width and height of all images by 200 x 200 then echo $content to website)

What I have tried:

i tried, but can't result:

$newWidth = 200;
$newHeight = 200;
$content = preg_replace( array('/width="\d+"/i', '/height="\d+"/i'), array(sprintf('width="%d"', $newWidth), sprintf('height="%d"', $newHeight)), $child_article[6]); 

How do I solve this problem?

解决方案

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