问题描述
有没有一种方法来检测使用libclang匿名枚举,而不依赖于在拼写名称的文本?
Python绑定到libclang包括功能检测C / C ++结构或联合是否使用匿名clang.cindex.Cursor.is_anonymous,这最终调用clang_Cursor_isAnonymous.
下面的示例说明这个问题。
进口SYS
从clang.cindex进口*高清的nodeinfo(N):
回报(n.kind,n.is_anonymous(),n.spelling,n.type.spelling)IDX = Index.create()#翻译单元正确解析
TU = idx.parse(sys.argv中[1],['-std = C ++ 11'])
断言(LEN(tu.diagnostics)== 0)在tu.cursor.walk_ preorder N():
如果n.kind == CursorKind.STRUCT_DECL和n.is_anonymous():
打印的nodeinfo(N)
如果n.kind == CursorKind.UNION_DECL和n.is_anonymous():
打印的nodeinfo(N)
如果n.kind == CursorKind.ENUM_DECL:
如果n.is_anonymous():
打印的nodeinfo(N)
其他:
打印'不正确',将nodeinfo(N)
,当上sample.cpp的运行
枚举
{
VAL = 1
};的struct
{
结构{};
联盟
{
INT X;
浮ÿ;
};
};
给出:
不正确(CursorKind.ENUM_DECL,假,'','(匿名在sample1.cpp枚举:1:1))
(CursorKind.STRUCT_DECL,诚然,'',的::(在sample1.cpp匿名结构:8:5))
(CursorKind.UNION_DECL,诚然,'',的::(在sample1.cpp匿名联合:9:5))
不幸的是 clang_Cursor_isAnonymous
仅适用于结构和联合,你可以从铛源$ C $ C看到
无符号clang_Cursor_isAnonymous(CXCursor C){
如果(!clang_isDeclaration(C.kind))
返回0;
常量申报* D = cxcursor :: getCursorDecl(C);
如果(常量RecordDecl * FD = dyn_cast_or_null< RecordDecl>(D))
返回FD-> isAnonymousStructOrUnion();
返回0;
}
于是退回到了 conf.lib.clang_Cursor_isAnonymous
中的确实没有什么新的游标类型已经被核对FIELD_DECL(仅用于结构和联合是真实的)
高清is_anonymous(个体经营):
检查记录是匿名的。
如果self.kind == CursorKind.FIELD_DECL:
返回self.type.get_declaration()。is_anonymous()
返回conf.lib.clang_Cursor_isAnonymous(个体经营)
您可以尝试提取当前元素的标识符( n您的样品中),并检查它是否存在,或为空
Is there a way to detect anonymous enumerations using libclang without relying on the text in the spelling name?
The python bindings to libclang include functionality to detect whether C/C++ structs or unions are anonymous using clang.cindex.Cursor.is_anonymous, which ends up calling clang_Cursor_isAnonymous.
The following sample demonstrates the issue.
import sys
from clang.cindex import *
def nodeinfo(n):
return (n.kind, n.is_anonymous(), n.spelling, n.type.spelling)
idx = Index.create()
# translation unit parsed correctly
tu = idx.parse(sys.argv[1], ['-std=c++11'])
assert(len(tu.diagnostics) == 0)
for n in tu.cursor.walk_preorder():
if n.kind == CursorKind.STRUCT_DECL and n.is_anonymous():
print nodeinfo(n)
if n.kind == CursorKind.UNION_DECL and n.is_anonymous():
print nodeinfo(n)
if n.kind == CursorKind.ENUM_DECL:
if n.is_anonymous():
print nodeinfo(n)
else:
print 'INCORRECT', nodeinfo(n)
Which when run on sample.cpp
enum
{
VAL = 1
};
struct s
{
struct {};
union
{
int x;
float y;
};
};
Gives:
INCORRECT (CursorKind.ENUM_DECL, False, '', '(anonymous enum at sample1.cpp:1:1)')
(CursorKind.STRUCT_DECL, True, '', 's::(anonymous struct at sample1.cpp:8:5)')
(CursorKind.UNION_DECL, True, '', 's::(anonymous union at sample1.cpp:9:5)')
Unfortunately clang_Cursor_isAnonymous
works only with structs and unions as you can see from clang source code in tools/libclang/CXType.cpp
unsigned clang_Cursor_isAnonymous(CXCursor C){
if (!clang_isDeclaration(C.kind))
return 0;
const Decl *D = cxcursor::getCursorDecl(C);
if (const RecordDecl *FD = dyn_cast_or_null<RecordDecl>(D))
return FD->isAnonymousStructOrUnion();
return 0;
}
So fallback to the conf.lib.clang_Cursor_isAnonymous
in clang.cindex.Cursor.is_anonymous does nothing new as cursor type has been already checked against FIELD_DECL (which is true only for structs and unions)
def is_anonymous(self):
"""
Check if the record is anonymous.
"""
if self.kind == CursorKind.FIELD_DECL:
return self.type.get_declaration().is_anonymous()
return conf.lib.clang_Cursor_isAnonymous(self)
You can try to extract identifier of current element (n in your sample) and check if it exists or is null
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