C：指针的动态数组结构数组

问题描述

我有一个结构，这些结构的二维数组：

  typedef结构{
烧焦exit_n;
焦炭exit_s;
烧焦exit_w;
烧焦exit_e;
}室;房地图[地图宽度] [地图高度]
 

我需要指针的结构数组。下面code编译，但我没有得到想要的结果。任何帮助吗？这是越来越真糊涂对我来说，任何的解释是AP preciated

 房间*室;
房间=（室*）malloc的（sizeof的（室*）* ROOM_NUM）;
[..]
客房[N] =图[room_x] [room_y];
[..]
 

解决方案

其实，我想你想

 室**室;
房间=（室**）的malloc（sizeof的（室*）* ROOM_NUM）;
[..]
客房[N] =＆放大器;图[room_x] [room_y];
 

这给你一个指针数组到你的房间。

I have a structure and a bidimensional array of those structs:

typedef struct {
char exit_n;
char exit_s;
char exit_w;
char exit_e;
} room;

room map[MAP_WIDTH][MAP_HEIGHT];

I need an array of pointers those structs. The following code compiles, but I don't get the wanted result. Any help? This is getting really confused to me, any explanation would be appreciated

room *rooms;
rooms = (room*)malloc(sizeof(room*) * ROOM_NUM);
[..]
rooms[n] = map[room_x][room_y];
[..]

解决方案

Actually, I think you want

room** rooms;
rooms = (room**)malloc(sizeof(room*) * ROOM_NUM);
[..]
rooms[n] = &map[room_x][room_y];

This gives you an array of pointers to your rooms.

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