问题描述
我要做到这更好的方法，而不需要硬code整数为 $ justPrices [$ i] ：
I am looking to do this a better way without the need to hardcode the integers for $justPrices[$i]:
$pricesResult = array_merge($justPrices[0], $justPrices[1], $justPrices[2], $justPrices[3]);
$ justPrices 是一个多维数组，其中包含每个阵列内4价格'乐队'。对于数据 $ justPrices 是例如：
$justPrices is a multidimensional array, containing 4 'bands' of prices within each array. The data for $justPrices being for example:
Array ( [0] => Array ( [0] => 40.95 [1] => 39.95 [2] => 39.45 [3] => 38.95 ) [1] => Array ( [0] => 45.80 [1] => 41.80 [2] => 41.50 [3] => 41.40 ) [2] => Array ( [0] => 45.95 [1] => 42.95 [2] => 41.95 [3] => 41.45 ) [3] => Array ( [0] => 50.00 [1] => 50.00 [2] => 50.00 [3] => 50.00 ) )
问题是，在 $ justPrices 阵列的数量将至少从2变化到10+。所以，我需要为 array_merge（）函数来改变依赖于在 $ justPrices 。我打算用这个简单的方法来获取内部阵列的金额 $ justPrices ：
The issue is that the amount of arrays within $justPrices will vary from at least 2 to 10+. So I need a way for the parameters for the array_merge() function to vary dependent on the amount of arrays within $justPrices. I was going to use this simple method to get the amount of arrays within $justPrices:
$justPricesMax = count($justPrices);
我可以写一个循环，我可能还在，我只是想知道是否有用于表面比较简单！
I could write a for loop, and I might still, I just wondered if there was a better method for what seems on the surface relatively simple!
推荐答案
如果你只是想压平的数组，你可以使用叫 array_merge 与 $ justPrices 的元素作为参数
If you just want to flatten the array, you can use call_user_func_array to call array_merge with the elements of $justPrices as parameters:
$flat = call_user_func_array('array_merge', $justPrices);
这相当于一个函数调用
$flat = array_merge($justPrices[0], $justPrices[1], … , $justPrices[count($justPrices)-1]);
这篇关于一个更好的PHP的array_merge的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！