问题描述
如果我们忽略存储容量，写入，高度一致的读取和事务性读取，并假设我们的应用程序只能执行最终一致的读取，那么是否成立？
If we ignore storage capacity, writes, strongly-consistent reads, and transactional reads, and assume that our app can only perform eventually-consistent reads, is the following true?
1 RCU =每秒最终8K读取
1 RCU = 1 eventual 8K read per second
因此，1 RCU =每天最终8K读取
Therefore, 1 RCU = 86,400 eventual 8K reads per day
拥有25个免费RCU =每天最终216万次免费读取8K
With 25 free RCU's = 2.16 million eventual 8K reads per day FREE
或每天有216万个免费RCU
Or 2.16 million free RCU's per day
如果平均查询读取200个项目，每个项目0.5k = 13个RCU，则
If the average query reads 200 items @ 0.5k per item = 13 RCU's
假设他们在应用程序上什么也不做，那么166,153个人可以做到这一点每天免费查询吗？
Assuming they do nothing else on the app, 166,153 people can make that one and only query every day for free?
推荐答案
是的，如果有166,153人每天打一次电话，但永远不会在同一时间打过电话（如果您每秒有多个呼叫，并且预配置了25个RCU，则超过25个RCU的呼叫将受到限制。）
Yes, if those 166,153 people make that call once a day but also never at the same time (if you have multiple calls per second and you provisioned 25 RCU, calls exceeding 25 RCU will be throttled).
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