问题描述
我有一个数据文件,其中有三列:
I have a data file which has three columns thus:
20010101 000000 0.833
20010101 000500 0.814
20010101 001000 0.794
20010101 001500 0.772
...
相当清楚的人眼,前两个是日期和时间。我需要把它们转换成一个POSIXct(或者其他的东西,如果它更好,但我有限的过去的经验处理时间戳在R是使用POSIXct)。通常,使用read.table将其拉入,我将使用:
As is fairly clear to human eyes, the first two are date and time. I need to convert them into a POSIXct (or something else if it's better, but my limited past experience of dealing with timestamps in R is to use POSIXct). Normally, having pulled it in with read.table, I would use:
df$DateTime <- as.POSIXct(paste(df$Date, df$Time), format="%Y%m%d %H%M%S")
但是,第二列似乎失去了前导零(可能是通过类型强制?),因此它不能正常工作。
However, the second column seems to lose its leading zeroes (probably through a type coercion?), and thus it doesn't work correctly.
我看过中的POSIXct的因子,以及,但都使用带有分隔符的时间,例如:,因此没有相同的问题。
I've looked at Combine date as integer and time as factor to POSIXct in R and Converting two columns of date and time data to one, but both are using times with delimiters such as :, and so don't have the same problem.
如何将这些列转换成POSIXct?
How can I convert these columns to a POSIXct, please?
推荐答案
你很亲密。以下简单强制将前两列作为字符串读取,从而保存前导零。
You were very close. The following "simply" forces the first two columns to be read as character strings, which saves the leading zeros.
R> df <- read.table(text="20010101 000000 0.833
20010101 000500 0.814
20010101 001000 0.794
20010101 001500 0.772",
+ header=FALSE, colClasses=c("character", "character", "numeric"),
+ col.names=c("Date", "Time", "Val"))
R> df
Date Time Val
1 20010101 000000 0.833
2 20010101 000500 0.814
3 20010101 001000 0.794
4 20010101 001500 0.772
现在您正在尝试只是工作:
Now what you were attempting "just works":
R> df$DateTime <- as.POSIXct(paste(df$Date, df$Time), format="%Y%m%d %H%M%S")
R> df
Date Time Val DateTime
1 20010101 000000 0.833 2001-01-01 00:00:00
2 20010101 000500 0.814 2001-01-01 00:05:00
3 20010101 001000 0.794 2001-01-01 00:10:00
4 20010101 001500 0.772 2001-01-01 00:15:00
R>
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