如何在 Ruby 中从字符串中去除前导和尾随引号

问题描述

我想在 Ruby 中从字符串中去除前导和尾随引号.引号字符将出现 0 次或 1 次.例如，以下所有内容都应转换为 foo,bar:

I want to strip leading and trailing quotes, in Ruby, from a string. The quote character will occur 0 or 1 time. For example, all of the following should be converted to foo,bar:

• "foo,bar"
• "foo,bar
• foo,bar"
• foo,bar

推荐答案

你也可以使用 chomp 函数，但不幸的是它只能在字符串的末尾工作，假设有一个反向 chomp，你可以:

You could also use the chomp function, but it unfortunately only works in the end of the string, assuming there was a reverse chomp, you could:

'"foo,bar"'.rchomp('"').chomp('"')

实现 rchomp 很简单:

class String
  def rchomp(sep = $/)
    self.start_with?(sep) ? self[sep.size..-1] : self
  end
end

请注意，您也可以使用效率稍低的版本进行内联:

Note that you could also do it inline, with the slightly less efficient version:

'"foo,bar"'.chomp('"').reverse.chomp('"').reverse

从 Ruby 2.5 开始，rchomp(x) 以 delete_prefix 和 chomp(x) 可用作 delete_suffix，这意味着您可以使用

Since Ruby 2.5, rchomp(x) is available under the name delete_prefix, and chomp(x) is available as delete_suffix, meaning that you can use

'"foo,bar"'.delete_prefix('"').delete_suffix('"')

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