使用c＃读取xml文件

本文介绍了使用c＃读取xml文件的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 29岁程序员，3月因学历无情被辞！ 我有一个xml文件如下：I have an xml file as follows:<root xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"><row><enum>SerialPort_NotWork</enum><english>Serial Port is not working restart the Computer</english></row><row><enum>SoftwareRun_DemoMode</enum><english>SOFTWARE WILL RUN IN DEMO MODE ONLY</english> Xml文件包含大约1000 +附近的许多行。我想编写一个接受的函数'Enum'值并返回相关的'英语'值。 我尝试过的方法： 我试过以下Xml file contains many rows near about 1000+.I want to write a function which accepts 'Enum' value and returns associated 'English' value.What I have tried:I tried followingpublic static string GetString(String code) { XmlDocument xml = new XmlDocument(); xml.Load(@"D:\xmlDoc\Eng_Language.xml"); string firstName = null; XmlNodeList xnList = xml.SelectNodes("/Root/Row[Enum='code']"); foreach (XmlNode xn in xnList) { firstName = xn["English"].InnerText; } return firstName; } 但我得到XmlNode计数为零。建议如何搜索英语值基于'枚举'值but i get XmlNode count zero.plz suggest how to search 'English' value based on 'Enum' value推荐答案/root/row/enum[.=\"code"]/parent::row/english 或代码;Or in code;class Program { // This returns an IEnumerable<string> in case there are many <row>s with the same <enum>s. static IEnumerable<string> GetEnglishString(XPathNavigator navigator, string code) { var path = String.Format("/root/row/enum[.=\"{0}\"]/parent::row/english", code); return navigator.Select(path).Cast<XPathNavigator>().Select(n => n.Value); } static void Main(string[] args) { var document = new XmlDocument(); document.Load(@"C:\Temp\XmlExample\Eng_Language.xml"); var navigator = document.CreateNavigator(); var notWorking = GetEnglishString(navigator, "SerialPort_NotWork").FirstOrDefault(); var demoMode = GetEnglishString(navigator, "SoftwareRun_DemoMode").FirstOrDefault(); Console.WriteLine("notWorking={0}", notWorking); Console.WriteLine("demoMode={0}", demoMode); }} 希望这会有所帮助， FredrikHope this helps,Fredrik public static string Get_XML_Text(string enumText) { try { System.Xml.XmlDocument doc = new System.Xml.XmlDocument(); //doc.LoadXml(File.ReadAllText("your xml file Path")); doc.LoadXml(@"<row><enum>SerialPort_NotWork</enum><english>Serial Port is not working restart the Computer</english></row><row><enum>SoftwareRun_DemoMode</enum><english>SOFTWARE WILL RUN IN DEMO MODE ONLY</english></row>"); string firstName = null; XmlNodeList xnList = doc.SelectNodes("/root/row/enum"); foreach (XmlNode item in xnList) { if (item.InnerText.Trim().Equals(enumText, StringComparison.InvariantCultureIgnoreCase)) { firstName = xnList.Item(0).ParentNode.SelectNodes("//english").Item(0).InnerText; break; } } return firstName; } catch (Exception) { throw; } } 如有任何问题请告诉我。if any issue then let me know.XmlDocument xdoc = XmlDocument.Load(@"D:\xmlDoc\Eng_Language.xml"); var nodes = xdoc.Descendants("row") .Where(x=>(string)x.Element("enum").Value == "code") .Select(x=>(string)x.Element("english").Value); 如需了解更多信息，请参阅： LINQ to XML [ ^ ] 基本查询（L INQ to XML） [ ^ ] LINQ to XML Overview [ ^ ] 针对XPath用户的XML到XML [ ^ ]For further information, please see:LINQ to XML[^]Basic Queries (LINQ to XML)[^]LINQ to XML Overview[^]LINQ to XML for XPath Users[^] 这篇关于使用c＃读取xml文件的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！ 上岸，阿里云！