整合了jsf2.0和spring 3.1以及hibernate 4.1

问题描述

我想整合jsf2.0和spring 3.1和hibernate 4.1。但tomcat有错误404：description所请求的资源（/jsfspringhiber/page/default.jsf）不可用。
出了什么问题？
以下是我的web.xml：

 <？xml version =1.0encoding =UTF-8？> 
< web-app xmlns：xsi =http://www.w3.org/2001/XMLSchema-instance
 xmlns =http://java.sun.com/xml/ns / javaee
 xmlns：web =http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd
 xsi：schemaLocation =http：//java.sun .com / xml / ns / javaee 
 http://java.sun.com/xml/ns/javaee/web-app_3_0.xsdversion =3.0> 
 
< display-name> jsfspringhiber< / display-name> 
 
 < listener> 
< listener-class> 
 org.springframework.web.context.ContextLoaderListener 
< / listener-class> 
< / listener> 
< listener> 
< listener-class> 
 org.springframework.web.context.request.RequestContextListener 
< / listener-class> 
< / listener> 
 
 < context-param> 
< param-name> javax.faces.PROJECT_STAGE< / param-name> 
<参数值>开发< /参数值> 
< / context-param> 
 
 < welcome-file-list> 
< welcome-file> faces / default.xhtml< / welcome-file> 
< / welcome-file-list> 
 
 < servlet> 
< servlet-name> Faces Servlet< / servlet-name> 
< servlet-class> javax.faces.webapp.FacesServlet< / servlet-class> 
  1< / load-on-startup> 
< / servlet> 
 
<！ - 使用JSF映射这些文件 - > 
< servlet-mapping> 
< servlet-name> Faces Servlet< / servlet-name> 
< url-pattern> / faces / *< / url-pattern> 
< / servlet-mapping> 
< servlet-mapping> 
< servlet-name> Faces Servlet< / servlet-name> 
< url-pattern> *。jsf< / url-pattern> 
< / servlet-mapping> 
< servlet-mapping> 
< servlet-name> Faces Servlet< / servlet-name> 
< url-pattern> *。faces< / url-pattern> 
< / servlet-mapping> 
< servlet-mapping> 
< servlet-name> Faces Servlet< / servlet-name> 
< url-pattern> *。xhtml< / url-pattern> 
< / servlet-mapping> 
 
< / web-app> 
  

解决方案

我使用maven。正确的答案是
的结构是：

i want to integrate jsf2.0 and spring 3.1 and hibernate 4.1. but tomcat has error 404:description The requested resource (/jsfspringhiber/page/default.jsf) is not available.what is wrong?following is my web.xml:

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xmlns="http://java.sun.com/xml/ns/javaee" 
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" 
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee 
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0">

  <display-name>jsfspringhiber</display-name>

  <!-- Add Support for Spring -->
  <listener>
    <listener-class>
        org.springframework.web.context.ContextLoaderListener
    </listener-class>
  </listener>
  <listener>
    <listener-class>
        org.springframework.web.context.request.RequestContextListener
    </listener-class>
  </listener>

  <!-- Change to "Production" when you are ready to deploy -->
  <context-param>
    <param-name>javax.faces.PROJECT_STAGE</param-name>
    <param-value>Development</param-value>
  </context-param>

  <!-- Welcome page -->
  <welcome-file-list>
    <welcome-file>faces/default.xhtml</welcome-file>
  </welcome-file-list>

  <!-- JSF mapping -->
  <servlet>
    <servlet-name>Faces Servlet</servlet-name>
    <servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
    <load-on-startup>1</load-on-startup>
  </servlet>

  <!-- Map these files with JSF -->
  <servlet-mapping>
    <servlet-name>Faces Servlet</servlet-name>
    <url-pattern>/faces/*</url-pattern>
  </servlet-mapping>
  <servlet-mapping>
    <servlet-name>Faces Servlet</servlet-name>
    <url-pattern>*.jsf</url-pattern>
  </servlet-mapping>
  <servlet-mapping>
    <servlet-name>Faces Servlet</servlet-name>
    <url-pattern>*.faces</url-pattern>
  </servlet-mapping>
  <servlet-mapping>
    <servlet-name>Faces Servlet</servlet-name>
    <url-pattern>*.xhtml</url-pattern>
  </servlet-mapping>

</web-app>

解决方案

i use maven. the correct answer is here.the structure is:

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