问题描述
嘿，
好的，所以使用以下代码：
//假设这已经充满了输入
String MyInput;
String [] MySplits;
MySplits = MyInput.split（" ;;"）;
我怎样才能确定返回多少字符串
MySplits而不从0到1,000,000迭代并等待
抛出异常？
谢谢，
迈克
Hey,
Okay, so with the following code:
// assume this is full of input already
String MyInput;
String [] MySplits;
MySplits = MyInput.split(";");
How can I determine how many strings were returned into
MySplits without iterating from 0 to 1,000,000 and waiting
for an exception to be thrown?
Thanks,
Mike
推荐答案
MySplits.length
MySplits.length
MySplits.length
MySplits.length
嗯嗯，这不是一个有效的借口作为一个字符串也有这个
。是的，所以我不知道为什么我错过了！双倍
ouch。
Mike
Uhhhh, nope that''s not a valid excuse as a String has that
too. Right, so I have no idea why I missed that!!! Double
ouch.
Mike
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