如何将逗号分隔的字符串解析成列表（注意事项）？

问题描述

我需要一个字符串，如：

I need to be able to take a string like:

'''foo, bar, "one, two", three four'''

into：

['foo', 'bar', 'one, two', 'three four']

我有一种感觉（来自#python的提示）解决方案将涉及shlex模块。

I have an feeling (with hints from #python) that the solution is going to involve the shlex module.

推荐答案

shlex模块解决方案允许转义的引号，一个引号转义另一个，所有花哨的东西shell支持。

The shlex module solution allows escaped quotes, one quote escape another, and all fancy stuff shell supports.

>>> import shlex
>>> my_splitter = shlex.shlex('''foo, bar, "one, two", three four''', posix=True)
>>> my_splitter.whitespace += ','
>>> my_splitter.whitespace_split = True
>>> print list(my_splitter)
['foo', 'bar', 'one, two', 'three', 'four']

转义引号示例：

>>> my_splitter = shlex.shlex('''"test, a",'foo,bar",baz',bar \xc3\xa4 baz''',
                              posix=True) 
>>> my_splitter.whitespace = ',' ; my_splitter.whitespace_split = True 
>>> print list(my_splitter)
['test, a', 'foo,bar",baz', 'bar \xc3\xa4 baz']

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