如何使用 AWK 将键值配对列表转换为带有列的表?

本文介绍了如何使用 AWK 将键值配对列表转换为带有列的表?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

我需要将数据集从键值配对列表(informix dbaccess 输出)转换为列式 csv.我相当肯定这可以用 awk 或 sed 轻松完成.

I need to convert a dataset from a key value paired list (informix dbaccess output) into a columned csv. I'm fairly certain this can be done easily with awk or sed.

UPDATE 解决方案需要是单行响应.我正在使用 NSH(基于 ZSH).所以一些典型的害羞"命令将不起作用.

UPDATE The solution needs to be a single line response. I am using NSH (which is based on ZSH). So some of the typical "bashy" commands will not work.

这是我的数据样本集:

part_no            100000001
date_part          2010-10-13 12:12:12
history_code       ABCD
user_id            rsmith
other_information   note: Monday, December 10
pool_no            101011777

part_no            100000002
date_part          2010-10-21 12:12:12
history_code       GHIJ
user_id            jsmith
other_information
pool_no            101011888

part_no            100000002
date_part          2010-10-27 12:12:12
history_code       LMNO
user_id            fevers
other_information   [Mail]
pool_no            101011999

part_no            100000003
date_part          2010-11-13 12:12:12
history_code       QXRT
user_id            sjohnson
other_information   note: Tuesday, August 31
pool_no            101011111

我需要它看起来像这样:

I need it to look like this:

part_no,date_part,history_code,user_id,other_information,pool_no
100000001,10/13/2010 12:12:12,ABCD,rsmith,note: Monday, December 10,101011777
100000002,10/21/2010 12:12:12,GHIJ,jsmith,,101011888
100000002,10/27/2010 12:12:12,LMNO,fevers,[Mail],101011999
100000003,11/13/2010 12:12:12,QXRT,sjohnson,note: Tuesday, August 31,101011111

推荐答案

您的问题不清楚，但这可能是您要找的:

Your question isn't clear but this MAY be what you're looking for:

$ cat tst.awk
BEGIN { RS=""; FS="\n"; OFS=","; ofmt="\"%s\"%s" }
{
   for (i=1; i<=NF; i++) {
       tag = val = $i
       sub(/[[:space:]].*/,"",tag)
       sub(/[^[:space:]]+[[:space:]]+/,"",val)
       tags[i] = tag
       vals[i] = val
    }
}
NR==1 {
    for (i=1; i<=NF; i++) {
        printf ofmt, tags[i], (i<NF ? OFS : ORS)
    }
}
{
    for (i=1; i<=NF; i++) {
        printf ofmt, vals[i], (i<NF ? OFS : ORS)
    }
}

$ awk -f tst.awk file
"part_no","date_part","history_code","user_id","other_information","pool_no"
"100000001","2010-10-13 12:12:12","ABCD","rsmith","note: Monday, December 10","101011777"
"100000002","2010-10-21 12:12:12","GHIJ","jsmith","other_information","101011888"
"100000002","2010-10-27 12:12:12","LMNO","fevers","[Mail]","101011999"
"100000003","2010-11-13 12:12:12","QXRT","sjohnson","note: Tuesday, August 31","101011111"

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