问题描述
我正在用C ++编写代码来处理复数.我也在练习操作符重载.所以我重载了*
(乘法运算符),现在我想在重载的/
(除法运算符)中使用重载运算符,但是当我使用*
时,它显示错误.这是代码:
I'm writing a code in c++ for handling Complex numbers. I was also practicing operator overloading too. So I overloaded *
(multiplication operator), now I want to use the overloaded operator in my overloaded /
(division operator), but when I'm using *
its showing error. Here is the code:
#include <iostream>
#include <cmath>
using namespace std;
class Imaginary
{
public:
//constructors
Imaginary(double a,double b):x(a),y(b){}
Imaginary():x(0.0),y(0.0){}
//setter methods for x and y
void Setx(double x) { this->x = x; }
void Sety(double y) { this->y = y; }
//getter methods for x and y
double Getx(){return this->x;}
double Gety(){return this->y;}
//overloaded operators
Imaginary operator+(Imaginary&);
Imaginary operator-(Imaginary&);
Imaginary operator*(Imaginary&);
Imaginary operator~();
Imaginary operator/(Imaginary&);
void print();
private:
double x;
double y;
};
Imaginary Imaginary::operator+(Imaginary &i){
Imaginary ti;
ti.Setx(this->x+i.x);
ti.Sety(this->y+i.y);
return ti;
}
Imaginary Imaginary::operator-(Imaginary &i){
Imaginary ti;
ti.Setx(this->x-i.x);
ti.Sety(this->y-i.y);
return ti;
}
Imaginary Imaginary::operator*(Imaginary &i){
Imaginary ti;
ti.Setx((this->x*i.x) - (this->y*i.y));
ti.Sety((this->y*i.x)+(this->x*i.y));
return ti;
}
Imaginary Imaginary::operator~(){
int y;
y = this->y;
this->y = -y;
return *this;
}
Imaginary Imaginary ::operator/(Imaginary &i){
Imaginary numerator,denominator,ti;
//i want to use here the overloaded *(multiplacation) operator
numerator = (*this) * (~i);//showing error
denominator = (*this) * (~i);//showing error
ti.Setx(numerator.Getx()/denominator.Getx());
ti.Sety(numerator.Gety()/denominator.Getx());
return ti;
}
void Imaginary::print(){
cout<<x;
if (y>0)
cout<<"+i"<<y<<endl;
else if (y<0)
cout<<"-i"<<abs(y)<<endl;
}
int main()
{
Imaginary res;
Imaginary z1(2,3);
Imaginary z2(1,-1);
z1.print();
z2.print();
/*res = z1+z2;
cout<<"Addition:-\n";
res.print();
res = z1-z2;
cout<<"Subtraction:-\n";
res.print()*/
res = z1*z2;
cout<<"Multiplication:-\n";
res.print();
res = z1/z2;
cout<<"Division:-\n";
res.print();
return 0;
}
错误消息如下:-
D:\Games\Cheese\main.cpp|66|error: no match for 'operator*' (operand types are 'Imaginary' and 'Imaginary')|
请任何人告诉我如何纠正它.
Please anybody show me how to rectify it.
推荐答案
在这种情况下,错误不是最好的错误.您的operator*
定义为
The error isn't the best one in this case. Your operator*
is defined as
Imaginary Imaginary::operator*(Imaginary &i)
要求右侧为左值.当你做
Which requires the right hand side to be an lvalue. When you do
(*this) * (~i)
在operator/
中的
,(~i)
返回作为右值的Imaginary
.您无法将该右值绑定到lavue参考,因此不会考虑您的重载,并且会出现编译器错误.
in operator/
, (~i)
returns Imaginary
which is a rvalue. You cannot bind that rvalue to the lavue reference so your overload is not considered and you get a compiler error.
解决此问题的最简单方法是采用const &
代替
The simplest way to fix this is to take a const &
instead like
Imaginary Imaginary::operator*(const Imaginary &i)
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