本文介绍了不在命名空间中捕获PDOException的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我不知道如何在下面的代码中捕获 PDOException
,请告诉我在下面的代码中throw throw在哪里?
I can't know how can i catch PDOException
in the follow code,please tell me where throw exception in the follow code?
我有(目录):
- folder
-1) b.php
-2) c.php
- autoloader
b $ b
在 b.php
中:
<?php
namespace folder;
use folder as x;
require_once '../autoload.php';
class b{
function __construct(){
print("<p>you are in class b<p/>");
}
}
$t=new x\c();
?>
和 c.php
:
and in c.php
:
class c{
function __construct(){
print("<p>you are in class c<p/>");
if(DB_TYPE == 'mysql')
$pdoString=DB_TYPE.':dbname='.DB_NAME.';host='.DB_HOST;
$pdoUsername=DB_USERNAME;
$pdoPass='1';//DB_PASS; in this line I enter wrong password
try{
$this->pdo = new PDO($pdoString, $pdoUsername, $pdoPass);
}catch(PDOException $e){ //we can't catch exception here!
die('<p> Error DataBase Connection: '.$e->getMessage()."</p>");
}
}
}
?>
我输入错误的密码,我期望在我的 catch
阻止但具有以下输出:
I enter wrong password,i expect that have catch the exception in my try catch
block but have this output:
you are in class c
Fatal error: Uncaught exception 'PDOException' with message 'SQLSTATE[HY000] [1045] Access denied for user 'root'@'localhost' (using password: YES)' in C:\xampp\htdocs\TEST\folder\c.php:17 Stack trace: #0 C:\xampp\htdocs\TEST\folder\c.php(17): PDO->__construct('mysql:dbname=kn...', 'root', '1') #1 C:\xampp\htdocs\TEST\folder\b.php(10): folder\c->__construct() #2 {main} thrown in C:\xampp\htdocs\TEST\folder\c.php on line 17
推荐答案
您在命名空间中。因此,PHP将寻找名为空格的类 folder\PDOException
,并尝试捕获(和失败)。
You are in a namespace. Hence, PHP will look for the namespaced class folder\PDOException
and attempt to catch that (And fail).
要使用全局命名空间,只需在类名后面添加一个反斜杠:
To use the global namespace, simply add a backslash behind the class name:
catch (\PDOException $e) {
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