本文介绍了删除 PySpark 数据框列中的最后几个字符的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个 PySpark DataFrame.如何从下面的 name
列中删除/删除最后 5 个字符 -
from pyspark.sql.functions 导入子串,长度valuesCol = [('rose_2012',),('jasmine_2013',),('lily_2014',),('daffodil_2017',),('sunflower_2016',)]df = sqlContext.createDataFrame(valuesCol,['name'])df.show()+--------------+|姓名|+--------------+|玫瑰_2012||茉莉花_2013||百合_2014||水仙花_2017||向日葵_2016|+--------------+
我想创建 2 列,flower
和 year
列.
预期输出:
+--------------+----+---------+|姓名|年份|花|+--------------+----+---------+|玫瑰_2012|2012|玫瑰||茉莉花_2013|2013|茉莉花||百合_2014|2014|百合||水仙花_2017|2017|水仙花||向日葵_2016|2016|亚花|+--------------+----+---------+
我创建的
year
列 -
df = df.withColumn("year", substring(col("name"),-4,4))df.show()+--------------+----+|姓名|年份|+--------------+----+|玫瑰_2012|2012||茉莉花_2013|2013||百合_2014|2014||水仙花_2017|2017||向日葵_2016|2016|+--------------+----+
我不知道怎么把最后5个字符砍掉,所以我只有花的名字.我通过调用 length
尝试了类似的方法,但这不起作用.
df = df.withColumn("flower",substring(col("name"),0,length(col("name"))-5))
如何创建只有花名的 flower
列?
解决方案
可以使用expr函数
>>>从 pyspark.sql.functions 导入子字符串、长度、col、expr>>>df = df.withColumn("flower",expr("substring(name, 1, length(name)-5)"))>>>df.show()+--------------+----+---------+|姓名|年份|花|+--------------+----+---------+|玫瑰_2012|2012|玫瑰||茉莉花_2013|2013|茉莉花||百合_2014|2014|百合||水仙花_2017|2017|水仙花||向日葵_2016|2016|向日葵|+--------------+----+---------+I am having a PySpark DataFrame. How can I chop off/remove last 5 characters from the column name
below -
from pyspark.sql.functions import substring, length
valuesCol = [('rose_2012',),('jasmine_2013',),('lily_2014',),('daffodil_2017',),('sunflower_2016',)]
df = sqlContext.createDataFrame(valuesCol,['name'])
df.show()
+--------------+
| name|
+--------------+
| rose_2012|
| jasmine_2013|
| lily_2014|
| daffodil_2017|
|sunflower_2016|
+--------------+
I want to create 2 columns, the flower
and year
column.
Expected output:
+--------------+----+---------+
| name|year| flower|
+--------------+----+---------+
| rose_2012|2012| rose|
| jasmine_2013|2013| jasmine|
| lily_2014|2014| lily|
| daffodil_2017|2017| daffodil|
|sunflower_2016|2016|subflower|
+--------------+----+---------+
year
column I have created -
df = df.withColumn("year", substring(col("name"),-4,4))
df.show()
+--------------+----+
| name|year|
+--------------+----+
| rose_2012|2012|
| jasmine_2013|2013|
| lily_2014|2014|
| daffodil_2017|2017|
|sunflower_2016|2016|
+--------------+----+
I don't know how to chop last 5 characters, so that I only have the name of flowers. I tried something like this, by invoking length
, but that doesn't work.
df = df.withColumn("flower",substring(col("name"),0,length(col("name"))-5))
How can I create flower
column with only flower names?
解决方案
You can use expr function
>>> from pyspark.sql.functions import substring, length, col, expr
>>> df = df.withColumn("flower",expr("substring(name, 1, length(name)-5)"))
>>> df.show()
+--------------+----+---------+
| name|year| flower|
+--------------+----+---------+
| rose_2012|2012| rose|
| jasmine_2013|2013| jasmine|
| lily_2014|2014| lily|
| daffodil_2017|2017| daffodil|
|sunflower_2016|2016|sunflower|
+--------------+----+---------+
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