在Derived.prototype = new Base中使用'new'关键字的原因是什么

添加了 _super code> instance更容易： function WeatherWidget（...） { WeatherWidget ._super.apply（this，arguments）; } 其他人已实施类似的扩展。 What does the following code do:WeatherWidget.prototype = new Widget;where Widget is a constructor, and I want to extend the Widget 'class' with a new function WeatherWidget.What is the new keyword doing there and what would happen if it is left out? 解决方案 WeatherWidget.prototype = new Widget;The new keyword calls Widget as a constructor and the return value is assigned to the prototype property. (If you would omit new, you would not call Widget unless you added an argument list, (). However, calling Widget that way might not be possible. It would certainly have the potential to spoil the global namespace if it is not strict mode code and the implementation is conforming to ECMAScript Ed. 5.x there, because then this in the constructor would refer to ECMAScript’s global object.)But this approach actually comes from a really viral bad example in the old Netscape JavaScript 1.3 Guide (mirrored at Oracle, formerly Sun).This way, your WeatherWidget instances will all inherit from the same Widget instance. The prototype chain will be:[new WeatherWidget()] → [new Widget()] → [Widget.prototype] → …This can be useful, but most of the time you would not want it to happen. You should not do that here unless you want all your WeatherWidget instances to share among them the property values they inherit from this Widget instance, and only through it, from Widget.prototype. Another problem is that you need to call the parent constructor this way, which may not allow to be called without arguments as you do, or would not initialize properly. It certainly has nothing to do with emulation of class-based inheritance as known, e.g., from Java.The proper way to implement class-based inheritance in these prototype-based languages is (originally devised by Lasse Reichstein Nielsen in comp.lang.javascript in 2003, for cloning objects):function Dummy () {}Dummy.prototype = Widget.prototype;WeatherWidget.prototype = new Dummy();WeatherWidget.prototype.constructor = WeatherWidget;(The constructor prototype property should be fixed as well, so that your WeatherWidget instances w would have w.constructor === WeatherWidget as expected, and not w.constructor === Widget. However, be aware that it is enumerable afterwards.)This way, WeatherWidget instances will inherit properties through the prototype chain, but will not share property values among them, because they inherit from Widget.prototype through Dummy which has no own properties:[new WeatherWidget()] → [new Dummy()] → [Widget.prototype] → …The parent constructor will only be called if you call it explicitly, from WeatherWidget, for example withfunction WeatherWidget (…){ Widget.apply(this, arguments);}(If you are in a very restricted environment that requires compliance with ECMAScript Ed. 5 and later – so not on the Web – or when implementations of ECMAScript Edition 5.1 have become ubiquitous – in 10 years or so from now, given that it took Edition 3 that long –, you can and should use WeatherWidget.prototype =Object.create(Widget.prototype, {constructor: {value: WeatherWidget}}); instead. This has the additional advantage that the resulting constructor property is not writable, enumerable, or configurable.)See also Function.prototype.extend() in my JSX:object.js for how to generalize this. Using that code, it would becomeWeatherWidget.extend(Widget);My Function.prototype.extend() takes an optional second argument with which you can easily augment the prototype of WeatherWidget instances:WeatherWidget.extend(Widget, { foo: 42, bar: "baz"});would be equivalent toWeatherWidget.extend(Widget);WeatherWidget.prototype.foo = 42;WeatherWidget.prototype.bar = "baz";You will still need to call the parent constructor explicitly in the child constructor, though; that part cannot reasonably be automated. But my Function.prototype.extend() adds a _super property to the Function instance which makes it easier:function WeatherWidget (…){ WeatherWidget._super.apply(this, arguments);}Other people have implemented similar extensions. 这篇关于在Derived.prototype = new Base中使用'new'关键字的原因是什么的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！ 上岸，阿里云！