问题描述
我有一些数据,例如 x
, y
和 z
.全部都是 1D
数组.我用 z
作为颜色做了一个散点图;
I have some data let say x
, y
, and z
. All are 1D
arrays. I have done a scatter plot with z
as color as;
import matplotlib.pyplot as plt
plt.scatter(x,y,c=z,alpha = 0.2)
plt.xlabel("X")
plt.ylabel("Y")
plt.ylim((1.2,1.5))
plt.colorbar()
z
值是标准化的,它介于 -1
到 1
之间.我已附上下图.
The z
values are normalized and its between -1
to 1
. I have attached the figure below.
我的问题是;如何过滤颜色,让颜色值介于 -0.25
到 0.25
之间的点从图形中消失(即将颜色设置为白色).
The question I have is; How can I filter the colors such that let say the points that have a color value between -0.25
to 0.25
disappear form the figure (i.e set the color to white).
如果需要回答这个问题,可以提供 x
、y
和 z
的值.感谢您的时间.
The values for x
, y
, and z
can be provided if needed to answer this question. Thank you for your time.
推荐答案
import matplotlib.pyplot as plt
import numpy as np
np.random.seed(42)
# prepare random data
stats = -1, 1, 200
x = np.random.uniform(*stats)
y = np.random.uniform(*stats)
z = np.random.uniform(*stats)
# mask unwanted data
thresh = 0.4
mask = np.abs(z) <= thresh
x_ma = np.ma.masked_where(mask, x)
y_ma = np.ma.masked_where(mask, y)
z_ma = np.ma.masked_where(mask, z)
然后进行绘图:
fig, (ax_left, ax_right) = plt.subplots(1, 2, figsize=(10, 4),
sharex=True, sharey=True)
img_left = ax_left.scatter(x, y, c=z)
fig.colorbar(img_left, ax=ax_left)
img_right = ax_right.scatter(x_ma, y_ma, c=z_ma)
fig.colorbar(img_right, ax=ax_right)
给出以下结果:
右侧的图隐藏了低于所选阈值的所有点.
The plot on the right side hides all points that fall below the chosen threshold.
这篇关于Matplotlib散点图过滤器颜色(Colorbar)的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!