使用当前位置数据时，CLGeocoder返回城市和州的空结果

问题描述

我正在尝试使用CLGeocoder获取城市和州的名称。但是，placemark.addressDictionary返回了我：

{
FormattedAddressLines =（
南大西洋
）;
名称=南大西洋;
Ocean =南大西洋；
}

，地标是：
南大西洋，南大西洋@ --- 42.60533670，-21.93128480> +/- 100.00m，区域CLCircularRegion（标识符：'半径4958095.65'，中心：，半径：4958095.65m）

Also ，[地标位置]的NSLog和[地标管理区域]都显示为nil。

还尝试添加ABAdressBookUI，ABAdressBook框架，并将数据获取为：

NSString * addressDict = ABCreateStringWithAddressDictionary（placemark.addressDictionary，NO）;

或尝试过：
NSString * state =（NSString *）[placemark.addressDictionary objectForKey：kABPersonAddressStateKey];

如果有任何可能的解决方案，或者如果我缺少某些内容，请告诉我。

点击当前位置按钮时的代码如下：

CLLocation * loc;

  loc = [[CLLocation alloc] initWithLatitude：[KLocationManager sharedManager] ._ locationManager.location.coordinate.latitude经度：[KLocationManager sharedManager] ._ locationManager.location.coordinate.longitude]; 
 
 CLGeocoder * geocoder = [[CLGeocoder alloc] init]; 
 
 [geocoder reverseGeocodeLocation：loccompleteHandler：^（NSArray * placemarks，NSError * error）{
 CLPlacemark * placemark = [placemarks objectAtIndex：0]; 
 if（placemark）{
 NSDictionary * dic = placemark.addressDictionary; 
 NSString * locName = [NSString stringWithFormat：@％@，％@，[dic objectForKey：@ City]，[dic objectForKey：@ State]]; 
 CLLocation * loc = placemark.location; 
 
 self.returnLocationDict = @ {@ name：locName，@ location：loc}; 
} 
}]； 
  

我在这里想念什么？

解决方案

复制您正在体验的一种方法是使用纬度和经度为0,0的CLLocation

我运行了您的

您的位置管理器可能未返回您期望的结果。

使用纬度：37.3318经度：-122.0312（无限循环..） p>

Hi I am trying to get the name of city and state using CLGeocoder. However, placemark.addressDictionary is returning me :

{ FormattedAddressLines = ( "South Atlantic Ocean" ); Name = "South Atlantic Ocean"; Ocean = "South Atlantic Ocean";}

and placemark is:South Atlantic Ocean, South Atlantic Ocean @ <-42.60533670,-21.93128480> +/- 100.00m, region CLCircularRegion (identifier:'<-41.51023865,-31.60774370> radius 4958095.65', center:<-41.51023865,-31.60774370>, radius:4958095.65m)

Also, NSLog of [placemark locality] and [placemark administrativeArea] shows both nil.

Also tried adding ABAdressBookUI , ABAdressBook framework and get the data as:

NSString *addressDict = ABCreateStringWithAddressDictionary(placemark.addressDictionary, NO); which returns an object with empty description.

or tried:NSString *state = (NSString *)[placemark.addressDictionary objectForKey:kABPersonAddressStateKey]; which throws warning of incompatible pointer types.

If there is any possible solution or if I am missing something please let me know.

My code when current location button is tapped is as follows:

CLLocation *loc;

loc = [[CLLocation alloc] initWithLatitude:[KLocationManager sharedManager]._locationManager.location.coordinate.latitude    longitude:[KLocationManager sharedManager]._locationManager.location.coordinate.longitude];

CLGeocoder* geocoder = [[CLGeocoder alloc] init];

[geocoder reverseGeocodeLocation:loc completionHandler:^(NSArray *placemarks, NSError *error) {
    CLPlacemark* placemark = [placemarks objectAtIndex:0];
    if (placemark) {
        NSDictionary* dic = placemark.addressDictionary;
        NSString* locName = [NSString stringWithFormat:@"%@, %@", [dic objectForKey:@"City"],[dic objectForKey:@"State"]];
        CLLocation* loc = placemark.location;

        self.returnLocationDict = @{@"name":locName, @"location":loc};
    }
}];

What am I missing here?

解决方案

One way of replicating what you're experiencing is to use a CLLocation with latitude and longitude of 0,0

I ran your code by using latitude:37.3318 longitude:-122.0312 (Infinite Loop..) and it worked as expected.

Your location manager is probably not returning what you expect.

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