为什么在raw_input期间无法捕获KeyboardInterrupt?

问题描述

这是一个测试用例.

try:
    targ = raw_input("Please enter target: ")
except KeyboardInterrupt:
    print "Cancelled"
print targ

当我按ctrl + c-

My output is as follows when I press ctrl+c-

NameError: name 'targ' is not defined

我的意图是将输出取消".有什么想法为什么当我尝试在raw_input期间捕获KeyboardInterrupt时会发生这种情况?

My intention is for the output to be "Cancelled". Any thoughts to as why this happens when I attempt to catch a KeyboardInterrupt during raw_input?

谢谢！

推荐答案

在上面的代码中，当引发异常时，未定义targ.您应该仅在未引发异常的情况下打印.

In above code, when exception raised, targ is not defined. You should print only when exception is not raised.

try:
    targ = raw_input("Please enter target: ")
    print targ
except KeyboardInterrupt:
    print "Cancelled"

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