问题描述
我在Quora的 C ++
代码中见过匿名类。它已成功编译并运行。
代码位于:
#include< iostream>
$ auto
$ public
int val;
} a;
a.val = 5;
返回a;
}
int main()
{
std :: cout<< func()。val<<的std :: ENDL;
返回0;
所以,它在C ++中有效吗?
另外,我很想知道,是否可以在C ++中使用匿名类?
<$ p $ p>
union {...};
它定义了一个未命名类型的未命名对象。它的成员被注入到周围的范围中,所以可以在不使用< object>。
前缀的情况下引用它们,否则将是必要的。
从这个意义上说,不存在匿名类(不是C ++联合中的联合是类)。
另一方面,,无名类(包括结构和联合)没有什么特别的。
union {...} x;
class {...} y;
typedef struct {...} z;
x
和 y
是未命名类型的命名对象。 z
是一个typedef名称,它是未命名结构的别名。他们不被称为匿名,因为这个词是保留给上述联合的形式。
[](){}
Lambdas是未命名类类型的未命名对象,但它们也不被称为匿名对象。
I have seen anonymous classes in C++
code on Quora. It's successfully compiled and run.
Code here:
#include <iostream>
auto func()
{
class // no name
{
public:
int val;
} a;
a.val = 5;
return a;
}
int main()
{
std::cout << func().val << std::endl;
return 0;
}
So, Is it valid in C++?
Also, I am curious to know, Is it possible to use anonymous classes in C++?
In C++, an anonymous union is a union of this form:
union { ... } ;
It defines an unnamed object of an unnamed type. Its members are injected in the surrounding scope, so one can refer to them without using an <object>.
prefix that otherwise would be necessary.
In this sense, no anonymous classes (that are not unions --- in C++ unions are classes) exist.
On the other hand, unnamed classes (including structs and unions) are nothing unusual.
union { ... } x;
class { ... } y;
typedef struct { ... } z;
x
and y
are named object of unnamed types. z
is a typedef-name that is an alias for an unnamed struct. They are not called anonymous because this term is reserved for the above form of a union.
[](){}
Lambdas are unnamed objects of unnamed class types, but they are not called anonymous either.
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