正则表达式，替换所有以@开头的单词

问题描述

我有这个正则表达式，将以@开头的所有单词放入span标记中.我已经完成了所需的工作，但是不确定我是否完全了解自己在这里所做的事情.

I have this regular expression that puts all the words that starts with @ into span tags.I've accomplished what is needed but i'm not sure that i completely understand what i did here.

content.replace(/(@\S+)/gi,"<span>$1</span>")

1. ()意味着匹配整个单词，对吧?
2. @表示以@开头.
3. \ S的意思是紧跟空格之前的所有内容".

但是，如果不在\ S后面加+号，那么它仅与第一个字母匹配，怎么会这样呢?

But how come that if don't add the + sign after the \S , it matches only the first letter?

任何输入将不胜感激.

推荐答案

\S是任何非空白字符，并且a+表示一个或多个.所以

\S is any non-whitespace character and a+ means one or more of a. So

@\S->一个@，后跟一个非空格字符.

@\S -> An @ followed by one non-whitespace character.

@\S+->一个@，后跟一个或多个非空白字符

@\S+ -> An @ followed by one or more non-whitespace characters

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