本文介绍了排毒_无法键入字符串,因为键盘未显示在屏幕上的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试使用排毒测试我的react-native app,等待文本输入可见并在其中键入文本。我的规范JS文件如下所示:
I'm trying to test my react-native app using detox, waiting for a text input to be visible and typing text in it. My spec JS file looks like this:
describe('FiestTest', () => {
beforeEach(async () => {
await device.reloadReactNative()
})
it('Login to a test account', async () => {
// LoginPage: entering phone number moving to next page
await expect(element(by.id('LoginPage-phoneInput'))).toBeVisible()
await element(by.id('LoginPage-phoneInput')).typeText('<someNumber>')
})
})
我得到的错误是:
FiestTest
1) Enter phone number and tap on button
0 passing (15s)
1 failing
1) FiestTest Enter phone number and tap on button:
Error: An action failed. Please refer to the error trace below.
Exception with Action: {
"Action Name" : "Type '6219'",
"Element Matcher" : "(((respondsToSelector(accessibilityIdentifier) && accessibilityID('ValidatePage-txtField')) && !(kindOfClass('RCTScrollView'))) || (kindOfClass('UIScrollView') && ((kindOfClass('UIView') || respondsToSelector(accessibilityContainer)) && ancestorThatMatches(((respondsToSelector(accessibilityIdentifier) && accessibilityID('ValidatePage-txtField')) && kindOfClass('RCTScrollView'))))))"
}
Error Trace: [
{
"Description" : "Failed to type string '6219', because keyboard was not shown on screen.",
"Error Domain" : "com.google.earlgrey.ElementInteractionErrorDomain",
"Error Code" : "2",
"File Name" : "GREYKeyboard.m",
"Function Name" : "+[GREYKeyboard typeString:inFirstResponder:error:]",
"Line" : "168"
}
]
我正在使用以下工具:
$ npm outdate
Package Current Wanted Latest Location
apollo-client 1.4.0 1.9.0 1.9.0 <appName>
babel-jest 19.0.0 19.0.0 20.0.3 <appName>
babel-plugin-module-resolver 2.7.0 2.7.1 2.7.1 <appName>
eslint 3.19.0 3.19.0 4.4.1 <appName>
eslint-plugin-import 2.2.0 2.7.0 2.7.0 <appName>
eslint-plugin-node 4.2.2 4.2.3 5.1.1 <appName>
eslint-plugin-react 6.10.3 6.10.3 7.1.0 <appName>
eslint-plugin-react-native 2.3.2 2.3.2 3.0.1 <appName>
graphql-tag 2.2.1 2.4.2 2.4.2 <appName>
jest 19.0.2 19.0.2 20.0.4 <appName>
moment-jalaali 0.6.1 0.6.1 0.7.0 <appName>
native-base 2.1.4 2.3.1 2.3.1 <appName>
react 16.0.0-alpha.6 16.0.0-alpha.6 15.6.1 <appName>
react-apollo 1.4.2 1.4.11 1.4.11 <appName>
react-native 0.44.0 0.44.0 0.47.1 <appName>
react-native-adjust 4.11.3 4.11.4 4.11.4 <appName>
react-native-fcm 6.2.3 6.2.3 8.0.0 <appName>
react-native-popup-menu 0.7.3 0.7.5 0.8.0 <appName>
react-native-router-flux 3.39.1 3.41.0 4.0.0-beta.16 <appName>
react-native-sentry 0.12.9 0.12.12 0.15.1 <appName>
react-native-smart-splash-screen 2.3.3 2.3.4 2.3.4 <appName>
react-test-renderer 15.4.2 15.4.2 15.6.1 <appName>
redux 3.6.0 3.7.2 3.7.2 <appName>
redux-persist 4.6.0 4.8.3 4.8.3 <appName>
这是我的podfile:
# Uncomment this line to define a global platform for your project
# platform :ios, '9.0'
target '<appName>' do
# Uncomment this line if you're using Swift or would like to use dynamic frameworks
# use_frameworks!
# Pods for <appName>
pod 'Firebase'
pod 'Firebase/Core'
pod 'Firebase/Analytics'
pod 'Firebase/Messaging'
pod 'Yoga', :path => '../node_modules/react-native/ReactCommon/yoga'
pod 'React', :path => '../node_modules/react-native', :subspecs => [
'RCTText',
'RCTImage',
'RCTNetwork',
'RCTWebSocket',
]
#target '<appName>-tvOSTests' do
# inherit! :search_paths
# Pods for testing
#end
#target '<appName>Tests' do
# inherit! :search_paths
# Pods for testing
#end
end
#target '<appName>-tvOS' do
# Uncomment this line if you're using Swift or would like to use dynamic frameworks
# use_frameworks!
# Pods for <appName>-tvOS
# target '<appName>-tvOSTests' do
# inherit! :search_paths
# Pods for testing
# end
#end
现在我只是使用像bellow这样的睡眠命令,以便给我时间手动插入字符串。但是,这不应该是一个永久的解决方案......
function sleep (ms) {
return new Promise(resolve => setTimeout(resolve, ms))
}
await sleep(milliseconds)
// what needs to happen after I manually enter the code
我也在GitHub的排毒问题上发表了评论,但是想知道是否有人有同样的经历并且已经在这里找到了解决方案。
I've also commented in a Detox issue on GitHub, but was wondering if anyone has had the same experience and has found a solution here.
感谢你的帮助!
推荐答案
你应该运行
await element(by.id('LoginPage-phoneInput')).tap();
之前
await element(by.id('LoginPage-phoneInput')).typeText('<someNumber>')
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