本文介绍了相乘在PHP两个数组的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我乘两个数组是一个挑战。
这就是我打算做的。

 数组1([0] => 2 [1] => 2)
数组2([0] => 8000.00 [1] => 1234.00)

每次我乘这一点,将其分解为4个,并返回一个结果,因为这

 阵列([0] => 16000 [1] => 16000 [2] => 2468 [3] => 2468)

然而,当我通过单一它得到正确的单个数据。
这里是我的code,我将AP preciate任何帮助,我可以得到的。谢谢

  $ =总阵列();
的foreach($ office_price为$价格){
    的foreach($ office_quantity为$数量){
        $总[] = $价格* $数量;
    }
}


解决方案

您遍历两个数组,所以你得到的每一个值的两倍。

如你所知,一个阵列建成使用键和值。

使用您的foreach到那个程度:

  $ =总阵列();
的foreach($ office_price为$关键=> $价格){
    $总[] = $价格* $ office_quantity [$关键];
}

您只需要循环一个阵列,并且通过使用具有相同密钥对第二阵列的价值,你得到正确的结果。

I have a challenge multiplying two arrays.this is what i intend doing

Array1 ( [0] => 2 [1] => 2 )
Array2 ( [0] => 8000.00 [1] => 1234.00 )

Every time i multiply this it breaks it down into 4 and returns a result as this

Array ( [0] => 16000 [1] => 16000 [2] => 2468 [3] => 2468 )

However when i pass single a single data it gets it right.Here is my code, i'll appreciate any help i can get. Thanks

$total = array();
foreach($office_price as $price){
    foreach($office_quantity as $quantity){
        $total[] = $price * $quantity;
    }
}
解决方案

You loop through both arrays, so you get every value twice.

As you know, an array is built up using keys and values.

Use your foreach to that extent:

$total = array();
foreach ($office_price as $key=>$price) {
    $total[] = $price * $office_quantity[$key];
}

You only need to loop one array, and by using the value from the second array with the same key, you get the proper result.

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09-12 10:55