向 Tkinter OptionMenu 添加命令?

问题描述

我正在用 Python 2.7.8 编写一些代码，其中包括 OptionMenu 小部件.我想创建一个 OptionMenu 在选项更改时调用函数，但我也希望在列表中找到可能的选项，因为我的最终 OptionMenu 将具有多种选择.

I'm writing some code in Python 2.7.8 which includes the OptionMenu widget. I would like to create an OptionMenu that calls a function when the option is changed but I also want the possible options to be found in a list, as my final OptionMenu will have many options.

我使用以下代码创建了一个调用函数的OptionMenu:

I have used the following code to create an OptionMenu that calls a function:

from Tkinter import*

def func(value):
    print(value)

root = Tk()

var = StringVar()
DropDownMenu=OptionMenu(root, var, "1", "2", "3", command=func)
DropDownMenu.place(x=10, y=10)

root.mainloop()

我还发现了以下代码，它创建了一个 OptionMenu，其中包含在列表中找到的选项:

I have also found the following code that creates an OptionMenu with options found in a list:

from Tkinter import*

root = Tk()

Options=["1", "2", "3"]
var = StringVar()
DropDownMenu=apply(OptionMenu, (root, var) + tuple(Options))
DropDownMenu.place(x=10, y=10)

root.mainloop()

如何创建一个 OptionMenu 来在选项更改时调用函数并从列表中获取可能的选项?

How would I create an OptionMenu that calls a function when the option is changed and gets the possible options from a list?

推荐答案

从来不需要直接应用调用，这就是为什么在 2.7 中不推荐使用而在 3.0 中消失的原因.而是使用 *seq 语法.只需将您所做的两件事结合起来.以下似乎可以满足您的需求.

There is never a need for a direct apply call, which is why is is dreprecated in 2.7 and gone in 3.0. Instead use the *seq syntax. Just combine the two things you did. The following seems to do what you want.

from tkinter import *

def func(value):
    print(value)

root = Tk()
options = ["1", "2", "3"]
var = StringVar()
drop = OptionMenu(root, var, *options, command=func)
drop.place(x=10, y=10)

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