如何创造的Rails付款时更新相关联的发票？

问题描述

在我的Rails应用程序4我有这两种模式：

 类发票＆LT;的ActiveRecord :: Base的

  ＃属性：日期，金额，open_amount等。

  has_and_belongs_to_many：金

结束
 

---

 类付款＆LT;的ActiveRecord :: Base的

  ＃属性：日期，金额等。

  has_and_belongs_to_many：发票

  after_save的：update_invoices

  ...

  私人

  高清update_invoices
    invoices.each做到|发票|
      new_open_amount = invoice.open_amount  - 量
      invoice.update_column（：open_amount，new_open_amount）
    结束
  结束

结束
 

现在，创建一个付款单发票的作品，并更新发票的 open_amount 预期。

但是，如果一次性支付被用于更新的两个（或以上）发票？

支付金额应分布在所有相关的发票，从具有最低 ID发票和与具有最高 ID发票结束。

例如，如果有三个发票的金额 100 每一个，并支付与创建的金额 250 ，则发票的 open_amount 取值应变成这样的：

• 发票1：0
• 发票2：0
• 发票3：50

如何才能实现这一目标？我试图用一个循环，但未能由于我缺乏红宝石技能。

感谢您的帮助。

解决方案

 高清update_invoices
    剩余=量
    invoices.sort_by {| I | i.id}。每做|发票|
      TMP = invoice.open_amount
      接下来，除非剩余＆GT; 0＃当钱没回报
      new_open_amount = 0
      如果剩余＆LT; invoice.open_amount
        new_open_amount = invoice.open_amount  - 剩余
      结束
      剩余=剩余 -  TMP
      invoice.update_column（：open_amount，new_open_amount）
    结束
  结束
 

In my Rails 4 application I have these two models:

class Invoice < ActiveRecord::Base

  # Attributes: date, amount, open_amount, etc.

  has_and_belongs_to_many :payments

end

---

class Payment < ActiveRecord::Base

  # Attributes: date, amount, etc.

  has_and_belongs_to_many :invoices

  after_save :update_invoices

  ...

  private

  def update_invoices
    invoices.each do |invoice|
      new_open_amount = invoice.open_amount - amount
      invoice.update_column(:open_amount, new_open_amount)
    end
  end

end

Right now, creating a payment for a single invoice works and updates the invoice's open_amount as expected.

But what if one payment is used to update two (or more) invoices?

The payment amount should be distributed over all associated invoices, starting with the invoice that has the lowest id and ending with the invoice that has the highest id.

For example, if there are three invoices with an amount of 100 each, and a payment is created with an amount of 250, then the invoice's open_amounts should turn out like this:

• Invoice 1: 0
• Invoice 2: 0
• Invoice 3: 50

How can this be achieved? I tried using a loop but failed due to my lack of Ruby skills.

Thanks for any help.

解决方案

  def update_invoices
    remaining = amount
    invoices.sort_by{|i| i.id }.each do |invoice|
      tmp = invoice.open_amount
      next unless remaining > 0  #when the money is gone return
      new_open_amount = 0
      if remaining < invoice.open_amount
        new_open_amount = invoice.open_amount - remaining
      end
      remaining = remaining - tmp
      invoice.update_column(:open_amount, new_open_amount)
    end
  end

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