问题描述
我无法将数据发送到要处理的php文件.我已经尝试了几乎所有内容,但找不到问题的根源.下面是一个php文件,在用户单击购买按钮后,该产品会将产品名称,价格和ID发送给checkout
函数.
I am having trouble sending data to a php file to be processed. I have tried just about everything but cannot find the source of the problem. Below is a php file that sends a product name, price, and ID to a checkout
function after a user clicks on a buy button.
<?php
$servername = "localhost";
$username = "root";
$password = "root";
$dbname = "Test";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT P1.Product_Name, S2.Price, P1.Product_ID FROM Product P1, Sale_Item S2 WHERE P1.Product_ID=S2.Product_ID AND P1.Category='Sports'";
$res = $conn->query($sql);
$counter=0;
while ($row = $res->fetch_assoc()){
$Product_Name = $row["Product_Name"];
$Price = $row["Price"];
$Product_ID = $row["Product_ID"];
echo ('<td><p></p>'.$row["Product_Name"].'<br>'.$row["Price"].'<p></p><input type="button" value="Buy" onclick="checkout(\'' . $Product_Name . '\', \'' . $Price . '\', \'' . $Product_ID . '\')"</td>');
$counter++;
if ($counter==3) {
$counter=0;
print "<br>";
}
}
$conn->close();
?>
然后是checkout
函数:
<script type="text/javascript">
function checkout(Product_Name, Price, Product_ID) {
//document.write(Product_Name, Price, Product_ID)
var theProduct_Name = Product_Name;
var thePrice = Price;
var theProduct_ID = Product_ID;
$.ajax({
type: "POST",
url: "http://localhost:8888/checkout.php",
data: {Product_Name: theProduct_Name, Price: thePrice, Product_ID: theProduct_ID},
});
window.location.assign("http://localhost:8888/checkout.php")
}
</script>
我正在使用MAMP的phpMyAdmin数据库.我的网址不正确吗?我尝试使用"http://localhost:8888/checkout.php"
和checkout.php
.以下是我需要处理数据的php文件.为了简单地学习如何发送数据,我只是在文件内部回显以确保它确实在发布.但是没有回声.
I am using MAMP's phpMyAdmin's database. Is my url incorrect? I've tried using "http://localhost:8888/checkout.php"
and just checkout.php
. Below is the php file where I need to process data. For simply learning how to send the data I am just echoing inside the file to make sure it is actually posting. But nothing is being echoed.
<?php
session_start();
$servername = "localhost";
$username = "root";
$password = "root";
$dbname = "Test";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$theProduct_Name = $_POST['Product_Name'];
$theProduct_ID = $_POST['Product_ID'];
$thePrice = $_POST['Price'];
echo $theProduct_Name.$theProduct_ID.$thePrice;
?>
我是网络编程的新手,因此将不胜感激任何帮助或提示.我已经看了几个小时了,似乎无法正常工作.
I am new to web-programming so any help or tips would be appreciated. I've been looking at this for hours now and cannot seem to get it to work.
推荐答案
使用Ajax时,请求由ajax发送,您可以在成功方法中看到响应.对操作网址的任何直接调用都会发送新请求,在这种情况下,该请求对于
When using Ajax, the request is sent by ajax and you can see the response in the success method. Any direct call to the action URL will sends new request which is empty in this case for the line
window.location.assign("http://localhost:8888/checkout.php")
删除该行代码并更改您的jQuery.Ajax,像下面这样,以查看响应是什么.
Remove that line of code and change your jQuery.Ajax like bellow to see what's the response.
var request = $.ajax({
type: "POST",
url: "http://localhost:8888/checkout.php",
data: {Product_Name: theProduct_Name, Price: thePrice, Product_ID: theProduct_ID},
dataType: "html"
});
request.done(function(msg) {
alert ( "Response: " + msg );
});
request.fail(function(jqXHR, textStatus) {
alert( "Request failed: " + textStatus );
});
这篇关于如何使用AJAX将数据发布到php文件的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!