本文介绍了无法使用类,因为它不是特质的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我已在此处上进行了学习为laravel构建验证服务.我现在尝试从我的一个控制器调用验证器时遇到问题.我看到了错误:

I have followed the tutorial here on building a validation service for laravel. I am having issues now when trying to call the validator from one of my controllers. I am seeing the error:

validController cannot use Portal\Service\Validation\Laravel\AppInstancesValidator - it is not a trait

这是我的控制器:

class validController extends BaseController {

   use \Portal\Service\Validation\Laravel\AppInstancesValidator;

   public function validateInstance() {
      $post = Input::all();

      $instVal = new AppInstancesValidator( App::make('validator'));

      return $instVal->with($post)->passes();
  }

}

和我的验证人:

namespace Portal\Service\Validation\Laravel;

use Portal\Service\Validation\ValidableInterface;

class AppInstancesValidator extends LaravelValidator implements ValidableInterface {


  protected $rules = array(
    'app_name' => 'required',
    'app_instance_name' => 'required',
    'app_instance_ip' => 'required|ip'
  );

}

推荐答案

尝试将use放在class声明之前:

<?php // namespace Portal\Controllers;

use \Portal\Service\Validation\Laravel\AppInstancesValidator;

class validController extends BaseController {

    public function validateInstance() {}

}

这篇关于无法使用类,因为它不是特质的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

07-04 23:47