在Python中从1循环到无穷大

问题描述

在C语言中，我会这样做:

In C, I would do this:

int i;
for (i = 0;; i++)
  if (thereIsAReasonToBreak(i))
    break;

如何在Python中实现类似的目的?

How can I achieve something similar in Python?

推荐答案

使用 itertools.count :

import itertools
for i in itertools.count():
    if there_is_a_reason_to_break(i):
        break

在Python2中，xrange()仅限于sys.maxint，对于大多数实际目的而言可能已足够:

In Python2 xrange() is limited to sys.maxint, which may be enough for most practical purposes:

import sys
for i in xrange(sys.maxint):
    if there_is_a_reason_to_break(i):
        break

在Python3中，range()可以提高很多，尽管不能达到无穷大:

In Python3, range() can go much higher, though not to infinity:

import sys
for i in range(sys.maxsize**10):  # you could go even higher if you really want
    if there_is_a_reason_to_break(i):
        break

因此，最好使用count().

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