本文介绍了OpenCV无法从网络摄像头捕获帧的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我使用OpenCV 2.4.6与VS2010。

I am using OpenCV 2.4.6 with VS2010.

我认为我的网络摄像机无法捕获帧。当我执行代码它构建成功,但我没有得到输出。我想,当我检查 if(!bSuccess)它被执行,并且无法捕获从网络摄像头的帧。

I think my webcam can't capture the frame. When I executed the code it built successfully, but I am not getting output. I think, when I check if(!bSuccess) it is executed and can't capture frame from the webcam.

如何解决此问题?我的代码如下:

How can I resolve this problem? My code is below:



#include "opencv2/highgui/highgui.hpp"
#include

using namespace cv;
using namespace std;

int main(int argc, char* argv[])
{
    VideoCapture cap(0); // open the video camera no. 0

    if (!cap.isOpened())  // if not success, exit program
    {
    cout  << "Cannot open the video file" << endl;
        return -1;
    }

   double dWidth = cap.get(CV_CAP_PROP_FRAME_WIDTH); //get the width of frames of the video
   double dHeight = cap.get(CV_CAP_PROP_FRAME_HEIGHT); //get the height of frames of the  video
    cout << "Frame size : " << dWidth << " x " << dHeight << endl;
    namedWindow("MyVideo",CV_WINDOW_AUTOSIZE); //create a window called "MyVideo"
    while (1)
    {
       Mat frame;
       bool bSuccess = cap.read(frame); // read a new frame from video
       if (!bSuccess) //if not success, break loop
        {
         cout << "Cannot read a frame from video file" << endl;
            break;
        }

        imshow("MyVideo", frame); //show the frame in "MyVideo" window

        if (waitKey(30) == 27)
        {
        cout << "esc key is pressed by user" << endl;
          break;
        }
    }
    return 0;

}


推荐答案

之前添加此行 cap.retrieve(frame);

bSuccess = cap.read(frame);

before line with bool bSuccess = cap.read(frame);

这篇关于OpenCV无法从网络摄像头捕获帧的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

07-04 22:52