问题描述
我想使用预测函数预测fjbjor何时为5.5，并且我总是收到此警告消息，并且我已经尝试了很多方法，但总是会出现这种情况，所以有人可以看到我在这里做错了什么吗
I am suppose to use the predict function to predict when fjbjor is 5.5 and I always get this warning message and I have tried many ways but it always comes so is there anyone who can see what I am doing wrong here
这是我的代码
fit.lm <- lm(fjbjor~amagn, data=bjor)
summary(fit.lm)
new.bjor<- data.frame(fjbjor=5.5)
predict(fit.lm,new.bjor)
这出来
1 2 3 4 5 6 7 8 9 10 11
5.981287 2.864521 9.988559 5.758661 4.645530 2.419269 4.645530 5.313409 6.871792 3.309773 4.200278
12 13 14 15 16
3.755026 5.981287 5.536035 1.974016 3.755026
如果任何人都能看到问题所在，我将非常感谢您的帮助.
If anyone can see what is wrong I would be really thankful for the help.
推荐答案
您的模型是fjbjor ~ amagn，其中fjbjor是响应，而amagn是协变量.那么您的newdata是data.frame(fjbjor=5.5).
Your model is fjbjor ~ amagn, where fjbjor is response and amagn is covariate. Then your newdata is data.frame(fjbjor=5.5).
newdata应该用于提供协变量而不是响应. predict将仅保留newdata中的协变量列.对于您指定的newdata，它将为NULL.结果，predict将使用内部模型框架进行预测，这将返回您拟合的值.
newdata should be used to provide covariates rather than response. predict will only retain columns of covariates in newdata. For your specified newdata, this will be NULL. As a result, predict will use the internal model frame for prediction, which returns you fitted values.
警告消息非常清楚. predict根据nrow(newdata)确定期望的预测数，即1.但是随后我发生了上述情况，因此返回了16个拟合值.这种不匹配会产生警告.
The warning message is fairly clear. predict determines the expected number of predictions from nrow(newdata), which is 1. But then what I described above happened so 16 fitted values are returned. Such mismatch produces the warning.
您真正想要的模型是:amagn ~ fjbjor.
Looks like the model you really want is: amagn ~ fjbjor.
这篇关于警告消息"newdata"有1行，但在R中找到的变量有16行的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！