为什么这样说-> TypeError:"bool"对象不可迭代

问题描述

内容只是一个文本文件

tokens = content.split()
topics = [e for (n, x) in enumerate(tokens) for (n2, x2) in enumerate(tokens) for (i, e) in enumerate(tokens) if any(x2.isdigit()) if '.' in x if re.findall('\D+', x) if n < i < n2]

我不明白我如何遍历bool，还有没有更简洁，更快捷的方式来进行列表理解?

I dont understand how I am iterating through a bool and also is there a more concise and faster way of doing this list comprehension?

推荐答案

您的问题来自-any(x2.isdigit())，我猜x2是一个字符串，所以x2.isdigit()返回一个bool，您不能使用any()功能.

Your issue comes from - any(x2.isdigit()) , I am guessing x2 is a string, so x2.isdigit() returns a bool , you cannot use any() function on it.

尝试不使用any()函数来检查x2是否为数字-

Try using without the any() function to check if x2 is a number -

if x2.isdigit()

如果要检查的是x2中是否包含数字，可以尝试-

If what you want to check is whether x2 has a digit in it or not, you can try -

if any(i.isdigit() for i in x2)

尽管我不知道您要做什么，所以无法检查其他逻辑是否正确.

Though I do not know what you are trying to do, so cannot check if the other logic is good or not.

any() 函数(列表或生成器表达式等)，以检查其中是否为True.

any() function is used on a iterable (lists or generator expression, etc) , to check if any of them is True.

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